Answer:
#6 would be 15/7
#7 would be 4/90
#8 would be 17/12
i can't see number 9
#11 would be 65/15 or 4.3333333
31 + 34
Step-by-step explanation:
Answer:
0.40
Step-by-step explanation:
to find out the probability that at least one of a pair of fair dice lands of 5, given that the sum of the dice is 8
Let A = sum of dice is 8
B = one lands in 5
P(B/A) = P(AB)/P(A) by conditional probability
P(AB) = sum is 8 and one is 5
So (5,3) or (3,5)
P(A) = sum is 8.
i.e. (2,6) (2,6) (3,5) (5,3) (4,4)
Required probability
= n(AB)/n(A)
=
Step-by-step explanation:
The Answer Is
-4d + 7 = 3d
So, 7 = 3d + 4d
Then, 7 = 7d
•d = 7/7
= 1
So D = 1.
Answer:
c. 9t+45 that shows distributive property
where it shows a*(b+c)=(a*b)+(b*c).so,9(t+5)=9*t+9*5
It’s c. Where the two planes intersect