Answer:
a) Right 0≤p<π/2 and 3π/2<p≤2π
left π/2 ≤ p ≤3π/2
stopped p=π/2 and p=3π/2
b) 5.5cm and its final position (2π, 0)
c) 6.5cm
Step-by-step explanation:
we must find where the function becomes negative, positive and zero
(according to the graph)
the particle moves to the right where the function is positive
0≤p<π/2 and 3π/2<p≤2π , the particle moves to the left where the function is negative π/2 ≤ p ≤3π/2, and stopped p=π/2 and p=3π/2
s(t)=∫v(t)dt also s(t) = 5sin(t)
(according to the graph 2)
The displacement of the particle is 5.5 and its final position
(2π, 0)
The total displacement of the particle is 6.5
Answer: =86
Step-by-step explanation:
* Hopefully the picture helps:) Mark me the brainliest:)
<em>∞ 234483279c20∞</em>
Answer:
50
Step-by-step explanation:
What I did was 2 divided by 100 = 0.02 Then multiply 0.02 times 500 and you should get 10 then multiply by how many years of interest and you get 50
<h3>hope this helped!</h3>
You're just changing the given rate into a unit rate: follow along and do the division shown and fill in the blanks. 320 ÷16 = 20
So the unit rate is
Answer:
This time all of them are right
I'm not writing this to achieve points, I have already actually check and read through it :D
Good work mate
Step-by-step explanation:
