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FrozenT [24]
2 years ago
14

Make a number line and mark the points that represent the following values of x. −5≤x≤34

Mathematics
1 answer:
castortr0y [4]2 years ago
5 0

The expression −5 ≤ x ≤ 34 is an inequality expression

<h3>How to draw the number line</h3>

The expression is given as:

−5 ≤ x ≤ 34

This can be split as follows:

−5 ≤ x and x ≤ 34

The inequalities used in the expression are less than or equal to.

This means that the endpoints of the inequality are inclusive of the values of x.

So, the value of x starts from -5, and it ends at 34

See attachment for the number line

Read more about number lines at:

brainly.com/question/10851163

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Lai Yee and Khadijah have 60 stamps. When Lai Yee gives 5 stamps to Khadijah, the number of Lai Yee's stamps is twice the number
Radda [10]

Answer:

Lai yee : 45

Khadijah : 15

Step-by-step explanation:

Here is the Explanation

8 0
3 years ago
5(x+4)= -2(-4-x)+3 <br> what is the answer?
lianna [129]

Answer:

x = -3

General Formulas and Concepts:

<u>Pre-Algebra</u>

  • Order of Operations: BPEMDAS
  • Equality Properties

Step-by-step explanation:

<u>Step 1: Define equation</u>

5(x + 4) = -2(-4 - x) + 3

<u>Step 2: Solve for </u><em><u>x</u></em>

  1. Distribute:                                   5x + 20 = 8 + 2x + 3
  2. Combine like terms:                   5x + 20 = 2x + 11
  3. Subtract 2x on both sides:        3x + 20 = 11
  4. Subtract 20 on both sides:        3x = -9
  5. Divide 3 on both sides:              x = -3

<u>Step 3: Check</u>

<em>Plug in x to verify it's a solution.</em>

  1. Substitute:                    5(-3 + 4) = -2(-4 - -3) + 3
  2. Simplify:                        5(-3 + 4) = -2(-4 + 3) + 3
  3. Add:                              5(1) = -2(-1) + 3
  4. Multiply:                        5 = 2 + 3
  5. Add:                              5 = 5

Here we see that 5 does indeed equal 5. ∴ x = -3 is a solution of the equation.

And we have our final answer!

5 0
3 years ago
Read 2 more answers
At a college, 69% of the courses have final exams and 42% of courses require research papers. Suppose that 29% of courses have a
laila [671]

Answer:

a) 0.82

b) 0.18

Step-by-step explanation:

We are given that

P(F)=0.69

P(R)=0.42

P(F and R)=0.29.

a)

P(course has a final exam or a research paper)=P(F or R)=?

P(F or R)=P(F)+P(R)- P(F and R)

P(F or R)=0.69+0.42-0.29

P(F or R)=1.11-0.29

P(F or R)=0.82.

Thus, the the probability that a course has a final exam or a research paper is 0.82.

b)

P( NEITHER of two requirements)=P(F' and R')=?

According to De Morgan's law

P(A' and B')=[P(A or B)]'

P(A' and B')=1-P(A or B)

P(A' and B')=1-0.82

P(A' and B')=0.18

Thus, the probability that a course has NEITHER of these two requirements is 0.18.

3 0
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D 19 in2
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A jar is filled up with buttons of various colors. Of the jar has a total of 875 buttons and 52% of buttons are green, how many
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Since 52% is the same as 52/100, we can multiply 875 by 52/100 in order to find the green buttons. 
52/100(875) = 455 
455 green marbles

3 0
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