In ΔHIJ, the measure of ∠J=90°, IH = 65, HJ = 56, and JI = 33. What is the value of the sine of ∠I to the nearest hundredth?
1 answer:
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Answer:
is the correct answer.
Step-by-step explanation:
We know that vertex equation of a parabola is given as:
where is the vertex of the parabola and
are the coordinate of points on parabola.
As per the question statement:
The parabola opens upwards that means coefficient of is positive.
Let
Minimum of parabola is at x = 3.
The vertex is at the minimum point of a parabola that opens upwards.
Putting value of a and h in the equation:
Formula used:
Comparing the equation formulated above with the options given we can observe that the equation formulated above is most similar to option A.
Comparing and
13 = 9+k
k = 4
Please refer to the graph attached.
Hence, correct option is
Answer:
x = 150°
Step-by-step explanation:
The given parameters are;
AB ║ DC
∠BAE = 105°
∠AEC = 25°
We construct a line CF from C parallel to the line AE as presented in the included diagram created with Microsoft Visio
We have;
∠DCF ≅ ∠BAE = 105° by similar angles formed by two pairs of parallel lines
∠AEC = ∠ECF = 25° by alternate interior angles formed by two parallel lines and a common transversal
x = 125° + 25° = 150° By angle addition postulate
x = 150°.
