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Temka [501]
2 years ago
9

What is the argument of the complex number shown? z=sqrt(2)/2 - sqrt(2)/2(i)

Mathematics
2 answers:
Rashid [163]2 years ago
8 0

Answer:

It’s not letting me comment on the last answer but can someone explain why it’s D??? Like I want to know how to solve the problem on my own.

Step-by-step explanation:

saveliy_v [14]2 years ago
5 0

Answer:7pi\4

Step-by-step explanation:

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The admission fee for a charity event is $7 for children and $10 for adults. The event was attended by 700 people and the total
Hitman42 [59]
X = 7
y = 10
x + y = 700
7x + 10y = 6400

10x + 10y = 7000
(-) 7x + 10y = 6400
______________
3x = 600
x = 200

200 + y = 700
y = 500
3 0
3 years ago
What the questions are asking help ASAP please
Rudiy27

Answer:

Step-by-step explanation:

A scalar is a constant value that is multiplied throughout a matrix.

e.g.

In number 1 the set up would look like this

3 * \left[\begin{array}{ccc}3&-1&5\\2&1&-4\\-6&3&2\end{array}\right]

To solve this, you must distribute the 3 to each value within the matrix

The solution to #1 would be

M = \left[\begin{array}{ccc}9&-3&15\\6&3&-12\\-18&9&6\end{array}\right]

3 0
3 years ago
Soap films and bubbles are colorful because the interference conditions depend on the angle of illumination (which we aren't cov
mylen [45]

Answer:

56.39 nm

Step-by-step explanation:

In order to have constructive interference total optical path difference should be an integral number of wavelengths (crest and crest should be interfered). Therefore the constructive interference condition for soap film can be written as,

2t=(m+\frac{1}{2} ).\frac{\lambda}{n}

where λ is the wavelength of light and n is the refractive index of soap film, t is the thickness of the film, and m=0,1,2 ...

Please note that here we include an additional 1/2λ phase shift due to reflection from air-soap interface, because refractive index of latter is higher.

In order to have its longest constructive reflection at the red end (700 nm)

t_1=(m+\frac{1}{2} ).\frac{\lambda}{2.n}\\ \\ t_1=\frac{1}{2} .\frac{700}{(2)*(1.33)}\\ \\ t_1=131.58\ nm

Here we take m=0.

Similarly for the constructive reflection at the blue end (400 nm)

t_2=(m+\frac{1}{2} ).\frac{\lambda}{2.n}\\ \\ t_2=\frac{1}{2} .\frac{400}{(2)*(1.33)}\\ \\ t_2=75.19\ nm

Hence the thickness difference should be

t_1-t_2=131.58-75.19=56.39 \ nm

7 0
2 years ago
Help ASAP please!!!
masya89 [10]
Total revenue the previous year would be $46,355
7 0
3 years ago
Read 2 more answers
How many solutions does the following system of equations have y=2x+2 & 2y=4x+4
iren [92.7K]

Answer:

y=2x + 2

0= 2x +2

-2x = 2

x= -1

Step-by-step explanation:

2y = 4x +4

2y -4x =4

y-2x =2

-2x +y =2

2x-y=-2

3 0
2 years ago
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