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3 years ago

Ill just casually give points away :)

Mathematics

2 answers:

Aleks [24]3 years ago

5 0

Answer:

Thank you

Explanation:

grin007 [14]3 years ago

4 0

Answer:

Thank you

Step-by-step explanation:

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Melissa can buy an 8 pound bag of dog food for $7.20. What is the cost of 1 pound? PLZZ I REALLY NEED HELP!

Furkat [3]

Answer:

$0.90

Step-by-step explanation:

7.20/8 = $0.90

6 0

2 years ago

How do I work this out??please help

serg [7]

The answer is x=5 because 24-3-5=16 so you have to get those 2 sides to equal 16....2*5=10+1=11 then add 5 and you get 16

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4 years ago

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You toss 3 fair coins in the air at once.

MAVERICK [17]

The probability of a head or tail upon flipping is 50-50. THe asnwers are as followsL
a. {HHH, HHT, HTT, TTT, TTH, THH, HTH, THT}b and c. p = 3C3 * 0.5^3 = 0.125d. from a, p = 3/8 = 0.375e. from a, p = 3/8 = 0.375f. 0.875

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4 years ago

The system of equations

Alex_Xolod [135]

Answer:

no solution

Step-by-step explanation:

y = x+1 and y = x + 2 don't touch because they are parallel

if you don't know what parallel means, just search it up, but i can explain it to you:

parallel means same slope or same steepness of line

7 0

3 years ago

Given f '(x) = (2 - x)(6 - x), determine the intervals on which f(x) is increasing or decreasing. (2 points)

weeeeeb [17]

Answer:

Decreasing (2, 6); increasing on (-∞, 2) U (6, ∞)

Step-by-step explanation:

To determine where $f(x)$ is increasing or decreasing, we set $f'(x)=0$ and check for the intervals.

We see that $f'(x)=0$ when either $x=2$ or $x=6$ . Therefore, we'll need to check the intervals $(-\infty,2)$ , $(2,6)$ , and $(6,\infty)$

For the interval $(\infty,2)$ , we can pick $x=0$ . This means that $f'(0)=(2-0)(6-0)=(2)(6)=12>0$ , showing that $f(x)$ increases on the interval $(-\infty,2)$

For the interval $(2,6)$ , we can pick $x=4$ . This means that $f'(4)=(2-4)(6-4)=(-2)(2)=-4$ , showing that $f(x)$ decreases on the interval $(2,6)$

For the interval $(6,\infty)$ , we can pick $x=7$ . This means that $f'(7)=(2-7)(6-7)=(-5)(-1)=5>0$ , showing that $f(x)$ increases on the interval $(6,\infty)$

Therefore, $f(x)$ is increasing on $(-\infty,2)\cup(6,\infty)$ and is decreasing on $(2,6)$ .

3 0

3 years ago