With any equation you are allowed to take the logarithm of both sides so
5^c=125 now take the logarithm base 5 to both sides giving.
log5(5^c)=log5(125), using the rule log(a^b)=a*log(b) you get
c log5(5)=log5(125), since log5(5)=1
c=log5(125)
Answer:
f(1)=-11
f(n)=f(n-1)+22
Step-by-step explanation:
Base equation:
f(n)=-11+22(n-1)
f(1)=-11+22(1-1)
f(1)=-11+0
f(1)=-11
f(n)=-33+22n
f(n-1)=-11+22(n-2)
f(n-1)=-55+22n
-33+22n=-55+22n+x
22n gets canceled out
-33=-55+x
-33+55=x
x=22
f(n)=f(n-1)+22
Answer:
it does not give us a graph so i cant help you sorry....
Step-by-step explanation:
Specific data is show I believe
Answer:
3 to 1
Step-by-step explanation:
