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krek1111 [17]
3 years ago
8

The students begin to play games. Each game takes 10 minutes

Mathematics
1 answer:
zvonat [6]3 years ago
4 0
What are you looking for?
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ASAP AND BRAINLIEST please please help guys im in a hurry
Vera_Pavlovna [14]

Answer:

(2, 1.5)

Step-by-step explanation:

Outlier Definition:  An outlier is defined as a data point that emanates from a different model than do the rest of the data.

The only one that stands out is (2, 1.5)

Answer:  (2, 1.5)

8 0
2 years ago
I dont get this question, anyone help me please
prisoha [69]
Its a line plot, for every number that is listed put a mark above the number on the number line. So if there was 3 6's, on the number line above the 6, put 3 marks like dots or x's to represent the amount of 6.
Hope you understand.
4 0
3 years ago
What is the surface area of this right rectangular prism with dimensions of 4 centimeters by 4 centimeters by 6 centimeters?
bagirrra123 [75]

Answer:

C

Step-by-step explanation:

This is because using the formula of area for shapes, you get this equation

A=2(wl+hl+hw)=2·(4·6+4·6+4·4)=128

7 0
2 years ago
Read 2 more answers
Use the diagram shown to find x.
marusya05 [52]
X would equal 70°.

For every triangle, all interior angles add up to 180°. This means that we can add together 42 and 68 to get 110°. Because the sum of all interior angles in a triangle must be 180°, we subtract 110 from 180 to see how much more we need, which gets us 70°.

I hope this helps!
6 0
3 years ago
Read 2 more answers
Given ACM, angle C=90º. AP=9, PM=12. Find AC, CM, AM.
Gnesinka [82]

Answer:

AM = 25, AC = 15, CM = 20

Step-by-step explanation:

The given parameters are;

In ΔACM, ∠C = 90°, \overline{CP} ⊥ \overline{AM}, AP = 9, and PM = 16

\overline{AC}² + \overline{CM}² = \overline{AM}²

\overline{AM} = \overline{AP} + PM = 9 + 16 = 25

\overline{AM} = 25

\overline{AC}² = \overline{AP}² + \overline{CP}² = 9² +  \overline{CP}²

∴ \overline{AC}² = 9² +  \overline{CP}²

Similarly we get;

\overline{CM}² = 16² + \overline{CP}²

Therefore, we get;

\overline{AC}² + \overline{CM}² = 9² +  \overline{CP}² + 16² + \overline{CP}² = \overline{AM}² = 25²

2·\overline{CP}² = 25² - (9² + 16²) = 288

\overline{CP}² = 288/2 = 144

\overline{CP} = √144 = 12

From \overline{AC}² = 9² +  \overline{CP}², we get

\overline{AC} = √(9² +  12²) = 15

\overline{AC} = 15

From, \overline{CM}² = 16² + \overline{CP}², we get;

\overline{CM} = √(16² + 12²) = 20

\overline{CM} = 20.

3 0
3 years ago
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