The students begin to play games. Each game takes 10 minutes

Perimeter of rectangle is 48 inches area is 40 inches what are the length of the side

Aloiza [94]

$\bf \textit{perimeter of a rectangle}=p=side+side+side+side
\\\\
or\implies p=w+w+l+l\implies p=2w+2l
\\\\
p=2(w+l)\qquad 
\begin{cases}
w=width\\
l=length\\
------\\
p=48
\end{cases}\implies 40=2(w+l)\\\\
-----------------------------\\\\
\textit{area of it}=A=w\cdot l\qquad \begin{cases}
w=width\\
l=length\\
------\\
A=40
\end{cases}\implies 40=wl\\\\
-----------------------------\\\\$

$\bf thus\qquad 
\begin{cases}
40=2(w+l)\to \frac{40}{2}=w+l\to\frac{40}{2}-l=\boxed{w}
\\\\
40=wl\\
--------------\\
40=\left( \boxed{\frac{40}{2}-l} \right)\cdot l
\end{cases}$

solve for "l" to find its length

7 0

2 years ago

What is the volume of a right circular cylinder with a diameter of 46. 25 cm and a height of 18. 5 cm? Enter your answer in the

Sedbober [7]

The volume of the right circular cylinder is 31064.54 cm³.

What is the formula for the volume of cylinder?

Formula:

V = πr²h.............. Equation 1

Since,

V = Volume of the right circular cylinder

r = radius of the base of the cylinder

h = height of the cylinder.

We have given that,

r = 46.25/2 = 23.125 cm

h = 18.5 cm

π = 3.14

We have to calculate volume of right circular cylinder.

Therefore,

Substitute these values into equation 1

V = 3.14(23.125²)(18.5)

V = 31064.54 cm³

Therefore

The volume of the right circular cylinder is 31064.54 cm³.

Learn more about the volume of a cylinder here:

brainly.com/question/1082469

3 0

2 years ago

Three times the difference of eight and twice a number is five times the number.

Softa [21]

Answer:

24

Step-by-step explanation:

3(2n-8)=5n distribute 3

6n-24=5n combine like terms

-24=-n divide by -1 on both sides

24=n

n=24

7 0

3 years ago

How do I go about solving (27x^3/8y^9)^5/3? And what is the role of the numerator and denominator?

MrRissso [65]

$\left( \frac{27x^3}{8y^9}\right)^ \frac{5}{3} \\\\\\ =\left( \frac{(3x)^3}{(2y^3)^3}\right)^ \frac{5}{3} \\\\\\ = \frac{(3x)^{3 \times \frac{5}{3} }}{(2y^3)^{3 \times \frac{5}{3} }} \\\\\\ =\frac{(3x)^5}{(2y^3)^{5 }} \\\\\\ =\frac{243x^5}{32y^{15}}$

Now, If the exponent was negative like you asked....

$\left( \frac{27x^3}{8y^9}\right)^ {-\frac{5}{3}} \\\\\\ =\left( \frac{8y^9}{27x^3}\right)^ {\frac{5}{3}}\\\\\\ =\left( \frac{(2y^3)^3}{(3x)^3}\right)^ \frac{5}{3} \\\\\\ = \frac{(2y^3)^{3 \times \frac{5}{3} }}{(3x)^{3 \times \frac{5}{3} }} \\\\\\ =\frac{(2y^3)^{5 }}{(3x)^5} \\\\\\ =\frac{32y^{15}}{243x^5}$

5 0

3 years ago

Help me please!!!! The question is in the picture^^^

Aleksandr [31]

Answer:

7,173

x = 7

Step-by-step explanation:

Within the question it gives two examples.

x = 0 corresponds to 2000

x = 1 corresponds to 2001

If you pay close attention the x-value is always the same as the last digits in the year. So with 2007 the last digit is 7, which then leads us to determine that

x = 7

f (x) = -327 (7) + 9462

f (x) = -2289 + 9462 = 7173

6 0

3 years ago