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miss Akunina [59]

2 years ago

11

Find the amount of simple interest that $400 would earn at 8% per year by the end of 3 years.

1 answer:

geniusboy [140]2 years ago

3 0

Answer:

400 times 8%= 32 times 3=96

Step-by-step explanation:

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The line plot shows the measurement of liquids in eight identical beakers. If you wanted to put the same amount of liquid in eac

yarga [219]

To find the amount of liquid that would be in each beaker, you would need to calculate the mean, or the average.

To do this you would create the following data set from your line plot.

1/8, 1/4, 3/8, 3/8, 3/8, 3/4, 3/4, 1

You would then add all these together and divide by 8.

4/8 = 1/2

The answer is B, 1/2 ml in each.

6 0

2 years ago

Helppppp!!!!!!!!!!!! Which of the following number sentences models the Associative Property of Multiplication?

grigory [225]

Answer:

b

Step-by-step explanation:

because I learned this like 4 years ago

8 0

2 years ago

Read 2 more answers

Name the place value to which each number was round 4.805 to 4.8

sesenic [268]

The place value is the tenths place

6 0

2 years ago

Identify the probability to the nearest hundredth that a point chosen randomly inside the rectangle is in the square. Only answe

wel

Answer:

$0.07$

Step-by-step explanation:

we know that

The probability that a point chosen randomly inside the rectangle is in the square is equal to divide the area of the square by the area of rectangle

Let

x-----> the area of square

y----> the area of rectangle

P -----> the probability

$P=\frac{x}{y}$

<em>Find the area of square (x)</em>

$A=5^{2}=25\ in^{2}$

<em>Find the area of rectangle (y)</em>

$A=25*15=375\ in^{2}$

Find the probability P

$P=\frac{25}{375}=0.07$

7 0

2 years ago

In a certain community, 36 percent of the families own a dog and 22 percent of the families that own a dog also own a cat. In ad

zysi [14]

Answer: a) 0.0792 b) 0.264

Step-by-step explanation:

Let Event D = Families own a dog .

Event C = families own a cat .

Given : Probability that families own a dog : P(D)=0.36

Probability that families own a dog also own a cat : P(C|D)=0.22

Probability that families own a cat : P(C)= 0.30

a) Formula to find conditional probability :

$P(B|A)=\dfrac{P(A\cap B)}{P(A)}\\\\\Rightarrow P(A\cap B)=P(B|A)\times P(A)$ (1)

Similarly ,

$P(C\cap D)=P(C|D)\times P(D)\\\\=0.22\times0.36=0.0792$

Hence, the probability that a randomly selected family owns both a dog and a cat : 0.0792

b) Again, using (2)

$P(D|C)=\dfrac{P(C\cap D)}{P(C)}\\\\=\dfrac{0.0792}{0.30}=0.264$

Hence, the conditional probability that a randomly selected family owns a dog given that it owns a cat = 0.264

5 0

3 years ago