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zubka84 [21]
3 years ago
11

Can somebody give me a PC? I broke my laptop and need a new one. I only have an android 4 phone, and I'm trying to do zoom, so p

lease I can't do assignments anymore without the PC, the phone barely handles zoom so thanks.....,
Mathematics
2 answers:
7nadin3 [17]3 years ago
8 0

Answer:

could you ask your school for a loner chromebook?

Step-by-step explanation:

Yuliya22 [10]3 years ago
6 0

Answer:

Search "The On It Foundation"

Step-by-step explanation:

or ask your school or local schools for a district issued one

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Use the graphing calculator to find the solution(s) of x2-2x-x 5 to the nearest tenth.
alexandr402 [8]

Answer:

-1.4 and 3.4

Step-by-step explanation:

The solutions of a quadratic are the x values of the x-intercepts where the function crosses the x-axis.

Type in your equation to graph. Then zoom in on the x-axis and find where the function crosses.

See attached picture.

7 0
3 years ago
Sean wrote a number on a piece of paper.
just olya [345]
The Sean's number is x. Formulate the equation:

x * 5 : 2 = 30
5x = 30 * 2
5x = 60
x = 60 : 5
x = 12

Answer: the Sean's number is 12.
8 0
3 years ago
John has a rectangular-shaped field whose length is 62.5 yards and width is 45.3 yards. The area of the field is ________ square
oee [108]
Area = 2831.25 square yards

Perimeter =215.6 yards

EXPLANATION

The area and perimeter of a rectangular field are found using the formula for finding the area and perimeter of a rectangle respectively.

That means, area of the rectangular field is given by the formula,

A= l\times w

We just have to substitute
l=62.5 and w= 45.3 into the given formula and evaluate.

This implies that;

A= 62.5\times 45.3

This gives the area of the rectangular-shaped field to be;

A= 2831.25 square yards.

Now for the perimeter, we use the formula

P=2w +2l

Or

P=2(w +l)

Substituting the values for the length and width gives,

P=2(62.5+45.3)

\Rightarrow P=2(107.8)

\Rightarrow P=215.6

Hence the perimeter of the rectangular shaped field is 215.6 yards.
8 0
3 years ago
Carter Road his bike 9/10 of a mile from his house to his grandmothers house. On his way back home, he rode 3/8 of a mile before
jek_recluse [69]

Answer:

Step-by-step explanation:

Carter rode his bike 9/10 of a mile from his house to his grandmothers house. This means that the distance from Carter's house to his grandmother's house is 0.9 miles. On his way back home, he rode 3/8 of a mile before the tyre on his bike went flat. This means that he rode 0.375 miles before his tyre went flat. The distance he must walk before he gets home will be the total distance from home minus the distance that he rode. It becomes

0.9 - 0.375 = 0.575 miles

3 0
3 years ago
Can someone pls help??
Vlad1618 [11]

Answer:

a. The y coordinates for A are either 10 or -14

b.  The y coordinates for A are either -11 or 7

Step-by-step explanation:

distance = sqrt ((x2-x1)^2+(y2-y1)^2)

We know Point B and the x coordinate of point A as well as the distance

15 = sqrt ((-4-5)^2+(-2-y1)^2)

15 = sqrt ((-9)^2+(-2-y1)^2)

15 = sqrt (81+(-2-y1)^2)

Square each side

15^2 =sqrt (81+(-2-y1)^2)^2

225 =  81+(-2-y1)^2

Subtract 81 from each side

225-81 = 81-81 +(-2-y1)^2

144 = (-2-y1)^2

Take the square root of each side

±sqrt 144 = sqrt(-2-y1)^2

±12 = (-2-y1)

Add 2 to each side

2±12 = 2-2-y1

2±12 = -y1

14 = -y1  or -10 = -y1

Multiply by -1

-14 = y1  or 10 = y1

The y coordinates for A are either 10 or -14

Now move B to -7,-2

15 = sqrt ((-7-5)^2+(-2-y1)^2)

15 = sqrt ((-12)^2+(-2-y1)^2)

15 = sqrt (144+(-2-y1)^2)

Square each side

15^2 =sqrt (144+(-2-y1)^2)^2

225 =  144+(-2-y1)^2

Subtract 144 from each side

225-144 = 144-144 +(-2-y1)^2

81 = (-2-y1)^2

Take the square root of each side

±sqrt 81 = sqrt(-2-y1)^2

±9 = (-2-y1)

Add 2 to each side

2±9 = 2-2-y1

2±9 = -y1

11 = -y1  or -7 = -y1

Multiply by -1

-11 = y1  or 7 = y1

The y coordinates for A are either -11 or 7

3 0
3 years ago
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