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Reil [10]
3 years ago
5

Subtract 8-4 1/2. A. 3 B. 4 C. 4 1/2 D. 3 1/2

Mathematics
2 answers:
SashulF [63]3 years ago
7 0
Think about it logically. The answer is 4 1/2, since 4 was subtracted from 8, and there is still the 1/2. 
Leokris [45]3 years ago
3 0
1.
An expression of the form a \frac{b}{c} is called a "compound fraction"
 
Compound fractions can be written as simple fractions by multiplying c to a, and then adding the product to c as follows:

a \frac{b}{c}= \frac{c.a+b}{c}

for example, 

4\frac{1}{2} can be written as: 

4\frac{1}{2}= \frac{2.4+1}{2}=\frac{9}{2}

2.

when we subtract or add a fraction \frac{m}{n} from an integer k, 

we first write k as a fraction with denominator n. We can do this as follows:

k=k. \frac{n}{n}= \frac{kn}{n}

for example, if we want to subtract \frac{9}{2} from 8, 

we first write 8 as a fraction with denominator 2:

8=8. \frac{2}{2}= \frac{8.2}{2}= \frac{16}{2}

3.

Thus, 

8-4 \frac{1}{2}= \frac{16}{2}- \frac{9}{2}= \frac{16-9}{2}= \frac{7}{2}

4.

The simple fraction 7/2 is not an option, so we write it as a compound fraction as follows:

\frac{7}{2}= \frac{6+1}{2}= \frac{6}{2}+ \frac{1}{2}=3+ \frac{1}{2}=3\frac{1}{2}

(So write 7 as the sum of the largest multiple of 2, smaller than 7 + what is left. In our case these numbers are 6 and 1, then proceed as shown)

5. Answer: D
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Classify each number according to its value.
Tems11 [23]

Answer:See below and attached

Step-by-step explanation:

Given numbers

4.2×10^-6, 2.1×10^-3, 3.1×10^-2, 3.2×10^-5, 3.5×10^-4, 5.8×10^-3, 5.2×10^-4

Greater than 3.1×10^-3

3.1×10^-2, 5.8×10^-3

Between 3.1 × 10^-3  and 4.3 × 10^-5

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Less than 4.3 × 10^-5

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Step-by-step explanation

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6 0
2 years ago
A special type of door lock has a panel with five buttons labeled with the digits 1 through 5. This lock is opened by a sequence
belka [17]

There are several ways the door can be locked, these ways illustrate combination.

There are 3375 possible combinations

From the question, we have:

\mathbf{n = 5} --- the number of digits

\mathbf{r = 3} ---- the number of actions

Each of the three actions can either be:

  • <em>Pressing one button</em>
  • <em>Pressing a pair of buttons</em>

<em />

The number of ways of pressing a button is:

\mathbf{n_1 = ^5C_1}

Apply combination formula

\mathbf{n_1 = \frac{5!}{(5-1)!1!}}

\mathbf{n_1 = \frac{5!}{4!1!}}

\mathbf{n_1 = \frac{5 \times 4!}{4! \times 1}}

\mathbf{n_1 = 5}

The number of ways of pressing a pair is:

\mathbf{n_2 = ^5C_2}

Apply combination formula

\mathbf{n_2 = \frac{5!}{(5-2)!2!}}

\mathbf{n_2 = \frac{5!}{3!2!}}

\mathbf{n_2 = \frac{5 \times 4 \times 3!}{3! \times 2 \times 1}}

\mathbf{n_2 = 10}

So, the number of ways of performing one action is:

\mathbf{n =n_1 + n_2}

\mathbf{n =5 + 10}

\mathbf{n =15}

For the three actions, the number of ways is:

\mathbf{Action = n^3}

\mathbf{Action = 15^3}

\mathbf{Action = 3375}

Hence, there are 3375 possible combinations

Read more about permutation and combination at:

brainly.com/question/4546043

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2 years ago
The width of a rectangle is seven less than one-fifth its length. If L is used to represent the length of the rectangle, then ho
Dima020 [189]

Answer:check the pic

Step-by-step explanation:

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I don't fully understand what you're asking.

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