Answer:
C.

Step-by-step explanation:

Answer:
d. 40 units
Step-by-step explanation:
The length of the horizontal side of this rectangle on the line y=20 is the difference of the x-coordinates, 12 and 20, so is 8. The length of the vertical side on the line x=20 is the difference of the y-coordinates, 20 and 8, so is 12.
Two sides are of length 8 and two are of length 12. The perimeter is the sum of the side lengths, so is ...
P = 2·8 +2·12 = 40 . . . units
3(n-t) = 3n- 3t
It is you mean about ?
Answer:
Linear and non-homogeneous.
Step-by-step explanation:
We are given that

We have to convert into y'+P(x)y=g(x) and determine P(x) and g(x).
We have also find type of differential equation.



It is linear differential equation because this equation is of the form
y'+P(x)y=g(x)
Compare it with first order first degree linear differential equation



Homogeneous equation

Degree of f and g are same.

Degree of f and g are not same .
Therefore, it is non- homogeneous .
Linear and non-homogeneous.