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vazorg [7]
3 years ago
9

Two pools are being drained. To start, the first pool had 3700 liters of water and the second pool had 4228 liters of water. Wat

er is being drained from the first pool at a rate of 31 liters per minute. Water is being drained from the second pool at a rate of 42 liters per minute.
Mathematics
1 answer:
cestrela7 [59]3 years ago
3 0

Answer:

Pool 1 will be drained out just over a minute before pool 2.

Step-by-step explanation:

Pool 1

3700/31 = 119.35minutes

Pool 2

4228/42 = 100.67minutes

Pool 1 will be drained out just over a minute before pool 2

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Answer:

true

Step-by-step explanation:

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(i) 809, 708, 607, _____, _ class 4<br>__class 4​
schepotkina [342]

Answer:

809, 708, 607, 506, 405, 304, 203, 102, 1, -100

Step-by-step explanation:

809, 708, 607, _____, _______

First term = 809

Second term = 708

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Difference between first term and second term = 809 - 708

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Difference between second term and third term = 708 - 607

= 101

Therefore, the common difference is 101

Fourth term = 607 - 101

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Fifth term = 506 - 101

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Sixth term = 405 - 101

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Seventh term = 304 - 101

= 203

Eighth term = 203 - 101

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Ninth term = 102 - 101

= 1

Tenth term = 1 - 101

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809, 708, 607, 506, 405, 304, 203, 102, 1, -100

4 0
2 years ago
What is the equivalent distance of 60,000 centimeters in kilometers?
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Step-by-step explanation:

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2 years ago
In a circle of radius 10 cm, a sector has an area of 40 (pi) sq. cm. What is the degree measure of the arc of the sector?
Rashid [163]

Answer:

144°

Step-by-step explanation:

First, find the area of the circle, with the formula A = \pir²

Plug in 10 as the radius, and solve

A = \pir²

A = \pi(10²)

A = 100\pi

Using this, create a proportion that relates the area of the sector to the degree measure of the arc.

Let x represent the degree measure of the arc of the sector:

\frac{40\pi }{100\pi } = \frac{x}{360}

Cross multiply and solve for x:

100\pix = 14400\pi

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So, the degree measure of the sector arc is 144°

6 0
3 years ago
Read 2 more answers
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