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Answer:
The frequency distribution is
The frequency distribution is
S/N Class limit Frequency
1 0-2 4
2 3 -4 1
3 5-6 2
4 7-8 2
5 9 - 10 0
6 11 - 12 0
The value for value upper class boundary of the fifth class is
Step-by-step explanation:
From the question we are told that
The lower class limit is 0
The class width is 2
The scores is 8,6,2,4,2,0,2,6,7
The frequency distribution is
S/N Class limit Frequency
1 0-2 4
2 3 -4 1
3 5-6 2
4 7-8 2
5 9 - 10 0
6 11 - 12 0
Generally the upper class boundary of the fifth class is mathematically represented as
The recursive formula would be:
This is because the first term, a₁, is 10. A recursive rule is dependent upon the term before it (a(n-1)) and the common ratio. The common ratio, or the number that each term is multiplied by, is -8.
This is because the first term, a₁, is 10. A recursive rule is dependent upon the term before it (a(n-1)) and the common ratio. The common ratio, or the number that each term is multiplied by, is -8.