168/3 = 56
<em>Therefore, Chad is driving the car in 56 mph.</em>
672/56 = 12
<em>Therefore, Chad drives 672 miles in 12 hours.</em>
308/11 = 28
<em>Therefore, Chad drives 28 miles per gallon of gas.</em>
672/28 = 24
<em>Therefore, Chad uses 24 gallons of gas to drive 672 miles.</em>
Answer:
Since the calculated z=40 falls in the critical region this indicates that the true obesity rate for children in Marion County is different from the national average at the 0.05 significance level. We reject the null hypothesis that population proportion is 0.17.
Step-by-step explanation:
The national average is 17% .The z proportional hypothesis test is used.
1) Let the null and alternate hypothesis be
H0: p =0.17
against the claim
Ha: p ≠ 0.17
Choose the significance level ∝= 0.05
The critical region is z > 1.96 and Z <- 1.96 because it is two tailed test.
Computing
z= p^-p / sqrt [pq/n]
Z= 0.22-0.17/ √0.17*(1- 0.17)/90147
z= 39.965
Since the calculated z=40 falls in the critical region this indicates that the true obesity rate for children in Marion County is different from the national average at the 0.05 significance level. We reject the null hypothesis that population proportion is 0.17.
23/6 = 3 and 5/6. You would just put the remainder over the number you divided by
Answer:
take away the 15 because you can't multiply a diagonal so 12x18=216 reduce it by the 15 would be the first one sir
Step-by-step explanation:
Answer:
Lower limit: 113.28
Upper limit: 126.72
Step-by-step explanation:
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean
and standard deviation
, the zscore of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:

Middle 60%
So it goes from X when Z has a pvalue of 0.5 - 0.6/2 = 0.2 to X when Z has a pvalue of 0.5 + 0.6/2 = 0.8
Lower limit
X when Z has a pvalue of 0.20. So X when 




Upper limit
X when Z has a pvalue of 0.80. So X when 



