The quote from the text that shows that the author’s purpose is to persuade is D. Critics say that kids stare at computers and TVs all day and do not get enough exercise. The facts stand in counterpoint to this belief.
An argumentative writing prompt is written in order to convince the readers about a particular issue.
According to the author, the fact that children are involved in watching movies, playing games, listening to music, etc doesn't mean that they can't still be productive.
There are some critics that believe that kids stare at computers and TVs all day and do not get enough exercise. This was countered by the author who stated that kids can still engage in exercises or do other productive things.
Read related link on:
brainly.com/question/24861556
Here's some code that might help, assuming that you are using JavaScript.
e = "Hello"
if(e === "Hello"){
alert(":D")
}else{
console.log("Um.")
}
I think that the answer is curly brackets.
Answer:
static int checkSymbol(char ch)
{
switch (ch)
{
case '+':
case '-':
return 1;
case '*':
case '/':
return 2;
case '^':
return 3;
}
return -1;
}
static String convertInfixToPostfix(String expression)
{
String calculation = new String("");
Stack<Character> operands = new Stack<>();
Stack<Character> operators = new Stack<>();
for (int i = 0; i<expression.length(); ++i)
{
char c = expression.charAt(i);
if (Character.isLetterOrDigit(c))
operands.push(c);
else if (c == '(')
operators.push(c);
else if (c == ')')
{
while (!operators.isEmpty() && operators.peek() != '(')
operands.push(operators.pop());
if (!operators.isEmpty() && operators.peek() != '(')
return NULL;
else
operators.pop();
}
else
{
while (!operators.isEmpty() && checkSymbol(c) <= checkSymbol(operators.peek()))
operands.push(operators.pop());
operators.push(c);
}
}
while (!operators.isEmpty())
operands.push(operators.pop());
while (!operands.isEmpty())
calculation+=operands.pop();
calculation=calculation.reverse();
return calculation;
}
Explanation:
- Create the checkSymbol function to see what symbol is being passed to the stack.
- Create the convertInfixToPostfix function that keeps track of the operands and the operators stack.
- Use conditional statements to check whether the character being passed is a letter, digit, symbol or a bracket.
- While the operators is not empty, keep pushing the character to the operators stack.
- At last reverse and return the calculation which has all the results.
Answer:
E-book : online edition of a new novel .
e-zine:online issue of today’s newspaper.
Online reference: online encyclopedia
blog: online website that posts restaurants reviews
Explanation:
Are you doing edge?
Also pleaseeeeeeeeeeeeeeeeeee mark me brainliest.
