The concept that can be used in order to answer this item is that of man-days. The total number of man-days required to do the job should always be constant.
This can be illustrated by the givens above.
Scenario 1:
N1 = (4 employees)(4 days) = 16 man-days
Scenario 2:
N2 = (2 employees)(8 days) = 16 man-days
The equation for determining the value of e is equal to,
k = (d)(e)
The answer is the second choice.
Answer:
The coordinates are (2,8)
Step-by-step explanation:
A hole is where both the numerator and the denominator are zero
f(x)=x^2+4x−12 / x−2
Factor the numerator
f(x) = (x+6) (x-2)/ (x-2)
The hole will occur where x-2 =0
x-2=0
Add 2 to each side
x-2+2 =0+2
x=2
There is a hole at x=2
If we could cancel the x-2 values from the top and bottom, we are left with
f(x) = x+6
At x=2
f(2) = 6+2
f(2) would be 8
The coordinates are (2,8)
There is a hole
Answer:
either 5 or 11
Step-by-step explanation:
(8, -12)
(5, -9) or (11, -9)
If y varies consistently with x then it would copy what happens, in a manner of speaking.
In this case, y increases by three, x would either add 3 or subtract 3
I am not completely sure on this.
Actually Welcome to the Concept of the Congruency,
Question 2.) => since all sides are equal, so SSS is the answer for Q-2
Question 3.) => Two angles and one side, so AAS is the answer for Q-3
