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2 years ago

What is the answer if you put a link you are getting reported

Mathematics

2 answers:

Alinara [238K]2 years ago

8 0

Answer:

its more than 3/4 :)

Step-by-step explanation:

zhannawk [14.2K]2 years ago

8 0

Answer:

true

Step-by-step explanation:

5+25+45=75

75÷100=3/4

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The number of students enrolled at hill school decreased by 120 students over an 8-year period. what was the average decrease in

MAVERICK [17]

120 divided by 8= 15

15 students per year is the answer.

8 0

2 years ago

How many sides does a parallelogram have?

aleksklad [387]

I'll give you a hint. A rectangle, a rhombus, and a square are all types of parallelograms. How many sides do they all have? Should come to you quick, good luck^^

4 0

2 years ago

Which of the following is equivalent to the complex number i^{6}

Helga [31]

$\bf \textit{recall that }i^2=-1
\\\\\\
i^6\implies i^{2+2+2}\implies i^2i^2i^2\implies (-1)(-1)(-1)$

and you know what that is.

4 0

2 years ago

Read 2 more answers

A flagpole is located at the edge of a sheer y = 70-ft cliff at the bank of a river of width x = 40 ft. See the figure below. An

Gnom [1K]

I would solve this using tangents. Let h be height of flagpole.
Set up 2 right triangles, each with a base of 40.
The larger triangle has height of "h+70"
Smaller triangle has height of 70.

Now write the tangent ratios:
$tan A = \frac{h+70}{40} , tan B = \frac{70}{40}$

Note: A-B = 9
To solve for h we need to use the "Difference Angle" formula for Tangent
$tan (A-B) = \frac{tanA - tanB}{1+tan A tan B}$
Plug in what we know:
$tan(9) = \frac{ \frac{h+70}{40} - \frac{70}{40}}{1+ (\frac{h+70}{40})(\frac{7}{4})}$
$tan (9) = \frac{ \frac{h}{40}}{ \frac{7h +650}{160}} = \frac{4h}{7h+650}$
$h = \frac{650 tan(9)}{4-7 tan(9)}$
$h = 35.6$

7 0

3 years ago

The amount of lateral expansion (mils) was determined for a sample of n = 8 pulsed-power gas metal arc welds used in LNG ship co

Alona [7]

Answer:

95% Confidence interval for the variance:

$3.6511\leq \sigma^2\leq 34.5972$

95% Confidence interval for the standard deviation:

$1.9108\leq \sigma \leq 5.8819$

Step-by-step explanation:

We have to calculate a 95% confidence interval for the standard deviation σ and the variance σ².

The sample, of size n=8, has a standard deviation of s=2.89 miles.

Then, the variance of the sample is

$s^2=2.89^2=8.3521$

The confidence interval for the variance is:

$\dfrac{ (n - 1) s^2}{ \chi_{\alpha/2}^2} \leq \sigma^2 \leq \dfrac{ (n - 1) s^2}{\chi_{1-\alpha/2}^2}$

The critical values for the Chi-square distribution for a 95% confidence (α=0.05) interval are:

$\chi_{0.025}=1.6899\\\\\chi_{0.975}=16.0128$

Then, the confidence interval can be calculated as:

$\dfrac{ (8 - 1) 8.3521}{ 16.0128} \leq \sigma^2 \leq \dfrac{ (8 - 1) 8.3521}{1.6899}\\\\\\3.6511\leq \sigma^2\leq 34.5972$

If we calculate the square root for each bound we will have the confidence interval for the standard deviation:

$\sqrt{3.6511}\leq \sigma\leq \sqrt{34.5972}\\\\\\1.9108\leq \sigma \leq 5.8819$

6 0

2 years ago