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This set up of a conversion table should show you that if you multiply the grams of BeI2 times .02 moles, it equals <span>5.256 g (your answer) </span>
Answer:
NO will be the limiting reagent.
Explanation:
The balanced equation is:
2 NO + 2 CO → N₂ + 2 CO₂
By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:
- NO: 2 moles
- CO: 2 moles
- N₂: 1 mole
- CO₂: 2 moles
Being the molar mass of each compound:
- NO: 30 g/mole
- CO: 28 g/mole
- N₂: 28 g/mole
- CO₂: 44 g/mole
Then by stoichiometry the following quantities of mass participate in each reaction:
- NO: 2 moles* 30 g/mole= 60 g
- CO: 2 moles* 28 g/mole= 56 g
- N₂: 1 mole* 28 g/mole= 28 g
- CO₂: 2 moles* 44 g/mole= 88 g
The limiting reagent is one that is consumed first in its entirety, determining the amount of product in the reaction. When the limiting reagent is finished, the chemical reaction will stop.
To determine the limiting reagent, you can use a simple rule of three as follows: If 56 grams of CO react with 60 grams of NO, 3 grams of CO react with how much mass of NO?
mass of NO= 3.21 grams
But 3.21 grams of NO are not available, 3 grams are available. Since you have less moles than you need to react with 3 grams of CO, <u><em>NO will be the limiting reagent. </em></u>
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