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2 years ago

3. Theoretically how many grams of magnesium is required to produce to 5.0 g of

Chemistry

1 answer:

FinnZ [79.3K]2 years ago

8 0

Answer:

3grams

Explanation:

The reaction for the production of Magnesium dioxide will be

Mg + O2 → MgO

we have 5g of MgO (molar mass 40g)

no of moles of MgO = 5/40 = 0.125

Using unitary method we have

1 mole of Mg require 1 mole of MgO

0.125 Mole of MgO = 0.125mole of Mg

n = given mass /molar mass

0.125 = mass / molar mass

mass = 0.125* 24 = 3grams

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2 years ago

If there are 80 liters of argon gas in a piston and the piston expands the gas until its volume is 2000 liters with a pressure o

Mice21 [21]

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Further Explanation:

Boyle's Law can be mathematically expressed as:

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In this problem, we are given the values:

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Plugging in these values into the equation:

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Keywords: gas, Boyle's Law, Ideal Gas Law

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2 years ago

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Mars2501 [29]

Answer:

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2 years ago

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densk [106]

Answer:

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2 years ago

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Masteriza [31]

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