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andrezito [222]
3 years ago
10

64g of sulfur dioxide (SO2) contains 32g of oxygen. Calculate how much sulfur it contains?

Chemistry
1 answer:
KengaRu [80]3 years ago
6 0
Mass of SO2 = mass of sulfur+ mass of oxygen
⇒ 64 g= mass of sulfur+ 32 g
⇒ mass of sulfur= 64 g-32 g
⇒ mass of sulfur= 32 g.

There is 32 g of sulfur in 64 g of SO2~
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Draw Au3N as a picture of atoms
Shkiper50 [21]

The picture of Au₃N is attached below.

The first part of the picture shows the formation of Au and N ions.

Formation of Au⁺¹ :

                            As Gold has one valence electron in 6s¹ therefore, it will loose it to form Au⁺¹. In case of Au₃N three atoms of Au looses three electrons to form three Au⁺¹ ions.

Formation of N⁻³ :

                            As Nitrogen has 5 valence elctrions therefore, it will gain three electrons that lost by Au to form Nitrite (i.e. N⁻³)

Formation of Au₃N:

                                Three cations of Au⁺ combines with one anion of N⁻³ to form a neutral ionic compound i.e. Au₃N as shown in second part of the picture.

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3 years ago
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Read 2 more answers
How many kilograms of a fertilizer are made of pure P2O5 would be required to supply 1.69 kilogram of phosphorus to the soil?
Alekssandra [29.7K]

Answer:

3.89 kg P2O5 must be used to supply 1.69 kg Phosphorus to the soil.

Explanation:

The molecular mass of P2O5 is

P2 = 2* 31 =           62

O5 = 5 *<u> 16 =         80</u>

Molecular Mass = 142

Set up a Proportion

142 grams P2O5 supplies 62 grams of phosphorus

x    kg P2O5        supplies 1.69 kg of phosphorus

Though this might be a bit anti intuitive, you don't have to convert the units for this question. The ratio is all that is important.

142/x = 62/1.69            Cross multiply

142 * 1.69 = 62x           combine the left

239.98 = 62x               Divide by 62

239.98/62 = x

3.89 kg of P2O5 must be used.

3 0
3 years ago
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