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3 years ago

64g of sulfur dioxide (SO2) contains 32g of oxygen. Calculate how much sulfur it contains?

1 answer:

6 0

Mass of SO2 = mass of sulfur+ mass of oxygen
⇒ 64 g= mass of sulfur+ 32 g
⇒ mass of sulfur= 64 g-32 g
⇒ mass of sulfur= 32 g.

There is 32 g of sulfur in 64 g of SO2~

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3 years ago

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Answer:

Explanation:

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3 years ago

PLEASE HELP!!!!!!

pogonyaev

Answer:

$m_{B}^{theoretical}=0.365gB$

$Y=87.1\%$

Explanation:

Hello there!

In this case, since the reaction (A->B) have an initial amount of pure 4-aminobenzoic acid, the first step to compute the theoretical yield is to solve the following stoichiometric setup:

$m_{B}^{theoretical}=0.303gA*\frac{1molA}{137.14gA}*\frac{1molB}{1molA}*\frac{165.19 gB}{1molB}\\\\ m_{B}^{theoretical}=0.365gB$

Whereas A stands for 4-aminobenzoic acid and B for the benzocaine. Moreover, we compute the percent yield by dividing the actual yield (0.318 g) by the theoretical one (0.365 g):

$Y=\frac{0.318g}{0.365g} *100\%\\\\Y=87.1\%$

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