Factors of 35: 1, 5, 7, 35
Of those, only 5 and 7 are prime.
7>5
Final answer: 7
Let's solve your equation step-by-step.
2x
/5 + 3 = x/10 - 1
Step 1: Simplify both sides of the equation.
2x
/5 + 3 = x/10 - 1
2/5x + 3 = 1/10x - 1
Step 2: Subtract 1/10x from both sides.
2/5x + 3 - 1/10x = 1/10x - 1 - 1/10x
3/10x + 3 = -1
Step 3: Subtract 3 from both sides.
3
/10x + 3 - 3 = -1 - 3
3/10x = -4
Step 4: Multiply both sides by 10/3.
(10/3) * (3/10x) = (10/3) * (-4)
x = -40/3
Answer:
1) 14
2) -8
Step-by-step explanation:
-2 × (-7) = 14
24 ÷ (-3) = -8
Answer:
Part 4) 
Part 5) 
Part 6) 
Step-by-step explanation:
Part 4) Find ER
we know that
In the right triangle ERF
Applying the Pythagorean Theorem

substitute the given values

solve for ER


Part 5) Find DF
we know that
In the right triangle DRF
Applying the Pythagorean Theorem

substitute the given values


simplify

Part 6) Find DE
we know that
----> by segment addition postulate
we have

substitute

Answer:
median number of snow days is 4
Step-by-step explanation:
Listed in order from least to greatest:
2
3
3
3
4
5
6
7
8
There are 9 numerals on this list. Because this count is odd, the median is simply the middle value, which here is 4. This is the median number of snow days.