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SVETLANKA909090 [29]
3 years ago
14

Air is made up mostly of O2, N2, and CO2. If the total pressure of air is 765mmHg and P(N2) = 0.79 atm and P(CO2) = 0.05 atm, th

en what is the partial pressure of the O2?
Chemistry
1 answer:
Mrac [35]3 years ago
5 0

Answer:

the partial pressure of the O2 is 0.167 atm

Explanation:

The computation of the partial pressure of the O2 is shown below:

As we know that

P = P_N2 + P_O2 + P_CO2

P_O2 = P - P_N2 -  P_CO2

= (1.007 - 0.79 - 0.05)

= 0.167 atm

Hence, the partial pressure of the O2 is 0.167 atm

we simply applied the above formula

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Which substance has a giant covalent structure and contains atoms of more than one element?A diamondB graphiteC methaneD sand
marysya [2.9K]

which substance has a giant covalent structure and contains atoms of more than one elements?

Explanation:

answer:methane

4 0
3 years ago
If 1.50g lead(II) nitrate is reacted with 1.75g sodium chromate what is the theoretical yield of the precipitate?
egoroff_w [7]

Answer:

1.46g of PbCrO₄ are the theoretical yield

Explanation:

Theoretical yield is defined as the maximum amount of products that could be produced (Assuming a yield of 100%).

The reaction of Lead (II) nitrate with sodium chromate is:

Pb(NO₃)₂(aq) + Na₂CrO₄(aq) → PbCrO₄(s) + 2NaNO₃ (aq)

First, we need to find molar mass of each reactant in order to determine limiting reactant (As the reaction is 1:1, the reactant with the lower number of moles is the limiting reactant). The moles of the limiting reactant = moles of Lead (II) chromate (The precipitate):

<em>Moles Pb(NO₃)₂ -Molar mass: 331.21g/mol-</em>

1.50g * (1mol / 331.21g) = 4.53x10⁻³ moles Pb(NO₃)₂

<em>Moles Na₂CrO₄ -Molar mass: 161.98g/mol-</em>

1.75g * (1mol / 161.98g) = 0.0108 moles

Pb(NO₃)₂ is limiting reactant and moles of PbCrO₄ are 4.53x10⁻³ moles. The mass is:

4.53x10⁻³ moles PbCrO₄ * (323.19g / mol) =

<h3>1.46g of PbCrO₄ are the theoretical yield</h3>
7 0
3 years ago
How many liters of oxygen are required to react completely with 1.2 liters of hydrogen to form water? 2H2(g) + O2(g) → 2H2(g)
Ira Lisetskai [31]

Answer:

\boxed{\text{0.60 L}}

Explanation:

We can use Gay-Lussac's Law of Combining Volumes to solve this problem.

Gases at the same temperature and pressure react in the same ratios as their coefficients in the balanced equation.

1. Write the chemical equation.

Ratio: 2 L     1 L

           2H₂ + O₂ → 2H₂O

V/L:   1.2

2. Calculate the volume of O₂.

According to Gay-Lussac, 1 L of O₂ forms from 2 L of H₂.

Then, the conversion factor is (1 L O₂/2 L H₂).

\text{Volume of O}_{2} = \text{1.20 L H}_{2}\times \dfrac{\text{1 L O}_{2}}{\text{2 L H}_{2}} = \textbf{0.60 L O}_{2}\\\\\text{You need }\boxed{\textbf{0.60 L of O}_{2}}

4 0
3 years ago
Compare how a positively charged object and a negatively charged object interact with a neutral object:
nlexa [21]
In the area of positive charge, neutral body gets negative charge for making a dipole whereas when negative charge bought near neutral one, it gets positive charge for the same reason.........making polarization
8 0
4 years ago
How many kilocalories are needed to vaporize 5.8 mol of Br2
Valentin [98]
<span>The vaporization of br2 from liquid to gas state requires 7.4 k/cal /mol.</span>
8 0
3 years ago
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