Answer:
Explanation:
We can use Gay-Lussac's Law of Combining Volumes to solve this problem.
Gases at the same temperature and pressure react in the same ratios as their coefficients in the balanced equation.
1. Write the chemical equation.
Ratio: 2 L 1 L
2H₂ + O₂ → 2H₂O
V/L: 1.2
2. Calculate the volume of O₂.
According to Gay-Lussac, 1 L of O₂ forms from 2 L of H₂.
Then, the conversion factor is (1 L O₂/2 L H₂).
Answer:
Two possible compounds are shown below- one with an exocyclic double bond and another one with an endocyclic double bond
Explanation:
Reaction of alkene with gives a complex of mercurous ion.
Then water molecule attacks this complex through type reaction at more substituted position.
cleaves the resultant C-Hg bond and forms a C-H bond.
Two possible structures of an alkene is possible to yield 1-methylcyclohexanol which are shown below.
The question is incomplete, here is the complete question:
The rate constant of a certain reaction is known to obey the Arrhenius equation, and to have an activation energy Ea = 71.0 kJ/mol . If the rate constant of this reaction is 6.7 M^(-1)*s^(-1) at 244.0 degrees Celsius, what will the rate constant be at 324.0 degrees Celsius?
<u>Answer:</u> The rate constant at 324°C is
<u>Explanation:</u>
To calculate rate constant at two different temperatures of the reaction, we use Arrhenius equation, which is:
where,
= equilibrium constant at 244°C =
= equilibrium constant at 324°C = ?
= Activation energy = 71.0 kJ/mol = 71000 J/mol (Conversion factor: 1 kJ = 1000 J)
R = Gas constant = 8.314 J/mol K
= initial temperature =
= final temperature =
Putting values in above equation, we get:
Hence, the rate constant at 324°C is