All categories

3 years ago

How do you get infinitely many solution?

Mathematics

1 answer:

vampirchik [111]3 years ago

3 0

Answer: I’m

Step-by-step explanation: I’d not knkw

You might be interested in

Let f and g be linear functions with equations f(x) = m1x + b1 and g(x) = m2x + b2.

MariettaO [177]

F(x) = m1x + b1
g(x) = m2x + b2

f(g(x)) = f(m2x + b2) = m1(m2x + b2) + b1 = m1m2x + b2 + b1

a.) f of g is also a linear function.

b.) slope is m1m2

8 0

3 years ago

Solve for x. 4 In (4x) = 16

sveticcg [70]

Answer:

x= 4

Step-by-step explanation:

4 x 4= 16

3 0

3 years ago

Read 2 more answers

Write an inequality that means 2 times a number (d) plus 3 is less than or equal to 9.

djyliett [7]

Answer: 2d+3<=9

Step-by-step explanation:2 times a number is 2d plus 3 is +3 less than or equal to is <=

5 0

2 years ago

The base of a cube is 36cm. What is the volume of the cube?

sasho [114]

Answer:

46656

Step-by-step explanation:

8 0

3 years ago

A= [2, 3; 2, 1], B=[3; 5]. Find AB & BA if possible

oksano4ka [1.4K]

Answer:

The value of AB is $\left[\begin{array}{ccc}21\\11\end{array}\right]$ and it's not possible to multiply BA.

Step-by-step explanation:

Consider the provided matrices.

$A=\left[\begin{array}{ccc}2&3\\2&1\end{array}\right]$ , $B=\left[\begin{array}{ccc}3\\5\end{array}\right]$

Two matrices can be multiplied if and only if first matrix has an order m × n and second matrix has an order n × v.

Multiply AB

Matrix A has order 2 × 2 and matrix B has order 2 × 1. So according to rule we can multiply both the matrix as shown:

$AB=\left[\begin{array}{ccc}2&3\\2&1\end{array}\right] \left[\begin{array}{ccc}3\\5\end{array}\right]$

$AB=\left[\begin{array}{ccc}2\times 3+3\times 5\\2\times 3+1\times 5\end{array}\right]$

$AB=\left[\begin{array}{ccc}6+15\\6+5\end{array}\right]$

$AB=\left[\begin{array}{ccc}21\\11\end{array}\right]$

Hence, the value of AB is $\left[\begin{array}{ccc}21\\11\end{array}\right]$

Now calculate the value of BA as shown:

Multiply BA

Matrix B has order 2 × 1 and matrix A has order 2 × 2. So according to rule we cannot multiply both the matrix.

We can multiply two matrix if first matrix has an order m × n and second matrix has an order n × v.

That means number of column of first matrix should be equal to the number of rows of second matrix.

Hence, it's not possible to multiply BA.

5 0

3 years ago