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2 years ago

The hexagon represents 1 whole. Explain

Mathematics

2 answers:

Black_prince [1.1K]2 years ago

6 0

Answer:

The hexagon is one whole

Step-by-step explanation:

This is because one whole shape = one whole so it is One whole of the hexagon

pshichka [43]2 years ago

5 0

Answer:

A hexagon is one whole because it has 2 halves

Step-by-step explanation:

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What is the slope intercept form of the graph

Bingel [31]

Answer:

y = x + 1

Step-by-step explanation:

y = mx + b

First, find the y-intercept. This is where the line intersects with the y-axis.

So, 1. -> y = mx + 1

Next, find the slope. For every 1/2 moving to the right, it also vertically increased by 1/2.

(1/2)/(1/2)

= 1 -> y = x + 1

Therefore, y = x + 1

7 0

2 years ago

Boxes of raisins are labled as containing 22 ounces. Following are the weights, in the ounces, of a sample of 12 boxes. It is re

kati45 [8]

Answer:

The 99 % confidence interval on the basis of mean is ( 21.7393 ; 22.0257)

Step-by-step explanation:

Mean = Sum of observations / Number of observations

Mean = 21.88 +21.76 +22.14 +21.63+ 21.81 +22.12+ 21.97+ 21.57+ 21.75+ 21.96 +22.20 +21.80/ 12

Mean =x`= 262.59/12= 21.8825

Standard Deviation = s= ∑x²/n - ( ∑x/n)²

∑x²/n= 478.7344 +473.4976 + 490.1796+467.8569+ 475.6761 + 489.2944+ 482.6809+ 465.2649+ 473.0625+ 482.2416 +492.84 + 475.24/ 12

∑x²/n= 5746.5689/12= 478.8807 = 478.881

Standard Deviation = s= ∑x²/n - ( ∑x/n)²

s= 478.881- (21.8825)²= 478.881-478.843= 0.037

The confidence limit 99% for the mean will be determined by

x` ± α(100-1) √s/n

Putting the values in the above equation

= 21.8825 ± 2.58 √0.037/12

Solving the square root

= 21.8825 ± 2.58 (0.05549)

Multiplying the square root with 2.58

=21.8825 ± 0.1432

Adding and subtracting would give

21.7393 ; 22.0257,

Hence the 99 % confidence interval on the basis of mean is ( 21.7393 ; 22.0257)

5 0

3 years ago

Can someone explain to me why are we adding 2kpi when we are doing zeros for sin and cos, but adding kpi when doing zeros for tg

makvit [3.9K]

on the first exercise, you got a solution angle of π/18, that's a good solution for the I Quadrant only, however, on a circle, we have angles that go from 0 to 2π, however we can always keep on going around and continute to 2π + π/2 or 3π or 4π, or 115π/3 or 1,000,000π/18 and so on, and we're really just going around the circle many times over, getting a larger and larger angle, same circular motion.

π/18 on that exercise works for the I Quadrant, however if we continue and go around say 2π, we'll find that 2π/3 + π/18 is a coterminal angle with π/18, and thus that angle has also the same sine value.

π/18 + 2kπ/3 , where k = integer, is a way to say, all angles around the circle that look like this have the same sine, namely

π/18 + 2(1)π/3

π/18 + 2(2)π/3

π/18 + 2(3)π/3

π/18 + 2(5)π/3

π/18 + 2(99999999)π/3

.....

so using the "k" as some sequence multiplier, is a generic notational way to say, "all these angles".

you'll also find that "n" is used as well for the same notation, say for example

2π/3 + 2πn.

8 0

2 years ago

So if i can buy 4 basketballs for $44 at the same rate how much would 8 basket balls be?

ch4aika [34]

$88 for 8 basketballs bc 1 ball is 11$ and 11(8)=88

7 0

2 years ago

Read 2 more answers

A frog jumps across a pond. Its height, as a function of time, is modeled by y

sdas [7]

Answer:The function is nonlinear

Step-by-step explanation:

6 0

2 years ago