Answer: 12.69 miles approx
Step-by-step explanation:
let x represent the number of miles traveled
1.75 + 0.65x = 10
0.65x = 8.25
x = 12.69 miles approx
Answer:
4. D
A: -25.5=a
B: b=-4
C: c=12
D: d=8
Step-by-step explanation:
4.Between a and d they are the 2 bigger values but D was the greatest out of all of them. - divided by a - will result as a positive and 7/9=0.77 and 19/12 *I looked for the least common factor and multiplied numerator and denominator to 12 depending on the denominators value. Ex: since one of my denominators was 4, I multiply the whole fraction by 3 to get 9/12 and the other was 5/6 times 2 is 10/12 and just add 10/12 by 9/12 which is 19/12.
5.
A: All I did was multiply 8.5 and -3 and get -25.5=a.
B: I add 7 on both sides of the equation and -7 and 7 get canceled off and -11+7=-4. b=4.
C: I multiplied - to -3 and got 3, now I can subtract -3 on both sides. 15-3=12 so c=12.
D. I had to divide by 4 on both sides to get d by itself. 32/4=8 so final answer would be d=8.
<h3>Given</h3>
1) Trapezoid BEAR with bases 11.5 and 6.5 and height 8.5, all in cm.
2) Regular pentagon PENTA with side lengths 9 m
<h3>Find</h3>
The area of each figure, rounded to the nearest integer
<h3>Solution</h3>
1) The area of a trapezoid is given by
... A = (1/2)(b1 +b2)h
... A = (1/2)(11.5 +6.5)·(8.5) = 76.5 ≈ 77
The area of BEAR is about 77 cm².
2) The conventional formula for the area of a regular polygon makes use of its perimeter and the length of the apothem. For an n-sided polygon with side length s, the perimeter is p = n·s. The length of the apothem is found using trigonometry to be a = (s/2)/tan(180°/n). Then the area is ...
... A = (1/2)ap
... A = (1/2)(s/(2tan(180°/n)))(ns)
... A = (n/4)s²/tan(180°/n)
We have a polygon with s=9 and n=5, so its area is
... A = (5/4)·9²/tan(36°) ≈ 139.36
The area of PENTA is about 139 m².
Answer:
The amount of Polonium-210 left in his body after 72 days is 6.937 μg.
Step-by-step explanation:
The decay rate of Polonium-210 is the following:
(1)
Where:
N(t) is the quantity of Po-210 at time t =?
N₀ is the initial quantity of Po-210 = 10 μg
λ is the decay constant
t is the time = 72 d
The decay rate is 0.502%, hence the quantity that still remains in Alexander is 99.498%.
First, we need to find the decay constant:
(2)
Where t(1/2) is the half-life of Po-210 = 138.376 days
By entering equation (2) into (1) we have:
Therefore, the amount of Polonium-210 left in his body after 72 days is 6.937 μg.
I hope it helps you!
Answer: x=18
Step-by-step explanation:
First distribute:
(18/6)-(x/6)=0
Isolate the x variable:
(18/6)=(x/6)
18=x