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Ksenya-84 [330]
3 years ago
8

WILL MARK THE BRAINLIEST

Mathematics
1 answer:
Anestetic [448]3 years ago
5 0

Answer:

Step-by-step explanation:

65.97in

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Which inverse operation would you use to solve the equation x/6-4=8
Artist 52 [7]
Hi there!

To find x, you would need to use the inverse of subtraction (addition) and inverse of division (multiplication), since you'd need to isolate x to one side of the equation to set x equal to a number. 

Hope this helps!
3 0
3 years ago
Math:
Dahasolnce [82]

Answer:

a) x_{1} = \frac{\pi}{3}\pm 2\pi \cdot i, \forall i \in \mathbb{N}_{O}, x_{2} = \frac{5\pi}{6}\pm 2\pi\cdot i, \forall i \in \mathbb{N}_{O}, b) x_{1} = \frac{\pi}{3}\pm 2\pi \cdot i, \forall i \in \mathbb{N}_{O}, x_{2} = \frac{5\pi}{3}\pm 2\pi\cdot i, \forall i \in \mathbb{N}_{O}

Step-by-step explanation:

a) The equation must be rearranged into a form with one fundamental trigonometric function first:

\sqrt{3}\cdot \csc x - 2 = 0

\sqrt{3} \cdot \left(\frac{1}{\sin x} \right) - 2 = 0

\sqrt{3} - 2\cdot \sin x = 0

\sin x = \frac{\sqrt{3}}{2}

x = \sin^{-1} \frac{\sqrt{3}}{2}

Value of x is contained in the following sets of solutions:

x_{1} = \frac{\pi}{3}\pm 2\pi \cdot i, \forall i \in \mathbb{N}_{O}

x_{2} = \frac{5\pi}{6}\pm 2\pi\cdot i, \forall i \in \mathbb{N}_{O}

b) The equation must be simplified first:

\cos x + 1 = - \cos x

2\cdot \cos x = -1

\cos x = -\frac{1}{2}

x = \cos^{-1} \left(-\frac{1}{2} \right)

Value of x is contained in the following sets of solutions:

x_{1} = \frac{\pi}{3}\pm 2\pi \cdot i, \forall i \in \mathbb{N}_{O}

x_{2} = \frac{5\pi}{3}\pm 2\pi\cdot i, \forall i \in \mathbb{N}_{O}

7 0
3 years ago
What is the slope of (-3,-6) and (4,7)​
Gelneren [198K]

Answer:

13/7

Step-by-step explanation:

m=(y2-y1)/(x2-x1)

m=(7-(-6))/(4-(-3))

m=(7+6)/(4+3)

m=13/7

3 0
3 years ago
What is the area of the triangle
ehidna [41]

Answer:

45.1 km^2

hope this helps

have a good day :)

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
Express in the form of p/q :<br><br> (i) 0.12▁3 (ii) 0. ▁621 (iii) 2.2▁18​
konstantin123 [22]

Answer:

1)0.123( bar on 3)

Let X = 0.123 ( bar on 3)

Then X = 0.1233 --------(1)

Multiply equation (1) by 100 we get,

100X = 12.33 --------(2)

Again multiply equation (2) by 10 we get,

1000X = 123.33 -------(3)

Subtract equation (2) from equation (3) we get,

1000X = 123.33

100X = 12.33

____________

900X = 111

X = 111/900

Hence,

0.123 ( bar on 3) is in the form of 111/900 which is in the form of P/Q.

6 0
3 years ago
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