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ivanzaharov [21]
3 years ago
13

Y=3x−7 what is the missing value

Mathematics
1 answer:
GaryK [48]3 years ago
5 0

Answer:

-21

Step-by-step explanation:

It would have to be -21 because there's -7, but the threes not negative so it would have to be -21

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Please answer correctly !!!!!!!!! Will mark brainliest !!!!!!!!!!!!!!!
Ugo [173]

Answer:

Step 3  they took the square root incorrectly

Step-by-step explanation:

5 ( x-2)^2 +6 = 86

Subtract 6 from each side

5 ( x-2)^2 +6 -6= 86-6

5 ( x-2)^2  = 80

Divide each side by 5

5 ( x-2)^2  /5 = 80/5

(x-2)^2 = 16

Take the square root of each side

sqrt((x-2)^2)  = ±sqrt(16)

x-2 = ±4

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3 years ago
Choose the statistical question. * please help now
Oliga [24]

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*me sweating while answering this*

Step-by-step explanation:

i think my dogs weigh about 50 pounds each

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Step-by-step explanation:

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3 years ago
A line segment is sometimes/always/never similar to another line segment, because we can sometimes/never/always map one into the
Fantom [35]

Answer:

A line segment is <u><em>always</em></u> similar to another line segment, because we can <u><em>always</em></u> map one into the other using only dilation a and rigid transformations

Step-by-step explanation:

we know that

A<u><em> dilation</em></u> is  a Non-Rigid Transformations that change the structure of our original object. For example, it can make our object bigger or smaller using scaling.

The dilation produce similar figures

In this case, it would be lengthening or shortening a line. We can dilate any line to get it to any desired length we want.

A <u><em>rigid transformation</em></u>, is a transformation that preserves distance and angles, it does not change the size or shape of the figure. Reflections, translations, rotations, and combinations of these three transformations are rigid transformations.

so

If we have two line segments XY and WZ,  then it is possible to use dilation and rigid transformations to map line segment XY to line segment WZ.

The first segment XY would map to the second segment WZ

therefore

A line segment is <u><em>always</em></u> similar to another line segment, because we can <u><em>always</em></u> map one into the other using only dilation a and rigid transformations

6 0
3 years ago
How do I solve
Maslowich

Use:\\\\(ab)^n=a^nb^n\\\\(a^n)^m=a^{nm}\\\\a^n\cdot a^m=a^{n+m}\\\\\sqrt[n]{a}=a^\frac{1}{n}\\------------------------\\\\\left(16n^4\right)^{\frac{5}{4}}=16^\frac{5}{4}\left(n^4\right)^\frac{5}{4}=16^{1\frac{1}{4}}n^{4\cdot\frac{5}{4}}=16^{1+\frac{1}{4}}n^5=16^1\cdot16^\frac{1}{4}\cdot n^5\\\\=16\cdot\sqrt[4]{16}\cdot n^5=16\cdot2\cdot n^5=\boxed{32n^5}\\\\\sqrt[4]{16}=2\ because\ 2^4=16\\\\\text{Answer}\ \boxed{\left(16n^4\right)^\frac{5}{4}=32n^5}

4 0
3 years ago
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