2 years ago

Determine the domain of the function.

Mathematics

1 answer:

pav-90 [236]2 years ago

4 0

$Domain \ of \ \frac{\sqrt{x + 3}}{(x + 8)(x - 2)}=(-3\leq x < 2) \cup (2 < x < \infty)$

i.e. x ≥ –3, x ≠ 2

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