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3 years ago

Determine the domain of the function.

Mathematics

1 answer:

pav-90 [236]3 years ago

4 0

$Domain \ of \ \frac{\sqrt{x + 3}}{(x + 8)(x - 2)}=(-3\leq x < 2) \cup (2 < x < \infty)$

i.e. x ≥ –3, x ≠ 2

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HOW MANY MORE DAYS UNTIL SUMMER.

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93 days until summer

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3 years ago

Read 2 more answers

Six is 20% of what number?

leonid [27]

Answer:

should be 30

Step-by-step explanation:

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2 years ago

The pie store is having a 55, percent off sale on all of its pies. If the pie you want regularly costs $7 how much would you sav

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This will come to 0.55*7 = $3.85

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3 years ago

Of 150 adults selected randomly from one town, 30 of them smoke. Construct a 99% confidence interval for the true percentage of

anyanavicka [17]

Answer:

The 99% confidence interval for the true percentage of all adults in the town that smoke is (0.1159, 0.2841).

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence interval $1-\alpha$ , we have the following confidence interval of proportions.

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which

z is the zscore that has a pvalue of $1 - \frac{\alpha}{2}$ .

For this problem, we have that:

Of 150 adults selected randomly from one town, 30 of them smoke. This means that $n = 150, p = \frac{30}{150} = 0.2$

99% confidence interval

So $\alpha = 0.01$ , z is the value of Z that has a pvalue of $1 - \frac{0.01}{2} = 0.995$ , so $Z = 2.575$ .

The lower limit of this interval is:

$\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.20 - 2.575\sqrt{\frac{0.20*0.80}{150}} = 0.1159$

The upper limit of this interval is:

$\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.20 + 2.575\sqrt{\frac{0.20*0.80}{150}}{119}} = 0.2841$

The 99% confidence interval for the true percentage of all adults in the town that smoke is (0.1159, 0.2841).

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3 years ago

Go to lesson page Problem If you flip three fair coins, what is the probability that you'll get a head on the first flip, a tail

ikadub [295]

The probability of any particular sequence of N flips of a fair coin is 2^(-N).

Your probability of the given sequence of 3 coin flips is
2^-3 = 1/8

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2 years ago