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3 years ago

Divide 1/2÷1/8 and express the answer in simplest terms. If necessary, use / for the fraction bar.

Mathematics

2 answers:

SVETLANKA909090 [29]3 years ago

7 0

Answer:

The answer for that problem would be 4.

Step-by-step explanation:

You would have to divide 1/2 by 1/8

Then you would have to flip it the equation so it is like this- 1/2 x 8/1

If you solve that you would get 4.

Hope this helps <3

Nitella [24]3 years ago

7 0

Answer: 4

see below for work :)

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3 years ago

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What is the value of n?

Schach [20]

Answer:

The value of n will be 8 centimeters.

Step-by-step explanation:

As we know that

Two chords at a point inside the circle.

The product of the segments of the intersecting chords are equal.

From the figure a attached below, the segments of one chord are 4 and 6 centimeters.

The segments of other cord are n and 3 centimeters.

As the product of the segments of the intersecting chords are equal.

$n\:\times\:3\:=\:4\:\times\:6$

$n\cdot \:3=24$

$\mathrm{Divide\:both\:sides\:by\:}3$

$\frac{n\cdot \:3}{3}=\frac{24}{3}$

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3 years ago

Read 2 more answers

For questions, 1-2, determine whether experiment is a binomial experiment. If it is, identify a success, specify the values of n

horrorfan [7]

Answer:

Part 1

X="number of U.S. households that own a dedicated game console"

Is a binomial experiment we an event defined with the associated probability and we have specific trials.

Let X the random variable of interest, on this case we now that:

$X \sim Binom(n=8, p=0.49)$

Y= "number of cards that are hearts."

Thats not a binomial experiment since the probability for each trial changes since we are doing the experiment without replacment

Part 2

a) $P(X=2)=(6C2)(0.39)^2 (1-0.39)^{6-2}=0.316$

b) $P(X \geq 5) = P(X=5)+P(X=6)$

$P(X=5)=(6C5)(0.39)^5 (1-0.39)^{6-5}=0.033$

$P(X=6)=(6C6)(0.39)^6 (1-0.39)^{6-6}=0.00352$

$P(X \geq 5) = P(X=5)+P(X=6)=0.033+0.00352=0.0365$

Part 3

Let X the random variable of interest, on this case we now that:

$X \sim Binom(n=6, p=0.34)$

The probability mass function for the Binomial distribution is given as:

$P(X)=(nCx)(p)^x (1-p)^{n-x}$

Part 4

$E(X)=np=4*0.69=2.76$

The variance $\sigma^2 = np(1-p) = 4*0.69*(1-0.69) =0.8556$

$\sigma=\sqrt{np(1-p)}=\sqrt{4*0.69(1-0.69)}=0.925$

Unusual outcomes would be considered values above or below 2 deviations from the mean for example 2.76-(2*0.925) =0.91 or 2.76+2(0.925)=4.61[/tex]. X=0 and X=4 would be considered as unusual values.

Step-by-step explanation:

Previous concepts

The binomial distribution is a "DISCRETE probability distribution that summarizes the probability that a value will take one of two independent values under a given set of parameters. The assumptions for the binomial distribution are that there is only one outcome for each trial, each trial has the same probability of success, and each trial is mutually exclusive, or independent of each other".

Part 1

X="number of U.S. households that own a dedicated game console"

Is a binomial experiment we an event defined with the associated probability and we have specific trials.

Let X the random variable of interest, on this case we now that:

$X \sim Binom(n=8, p=0.49)$

Y= "number of cards that are hearts."

Thats not a binomial experiment since the probability for each trial changes since we are doing the experiment without replacment

Part 2

Let X the random variable of interest, on this case we now that:

$X \sim Binom(n=6, p=0.39)$

The probability mass function for the Binomial distribution is given as:

$P(X)=(nCx)(p)^x (1-p)^{n-x}$

Where (nCx) means combinatory and it's given by this formula:

$nCx=\frac{n!}{(n-x)! x!}$

And we want to find this probability:

a) $P(X=2)=(6C2)(0.39)^2 (1-0.39)^{6-2}=0.316$

b) $P(X \geq 5) = P(X=5)+P(X=6)$

$P(X=5)=(6C5)(0.39)^5 (1-0.39)^{6-5}=0.033$

$P(X=6)=(6C6)(0.39)^6 (1-0.39)^{6-6}=0.00352$

$P(X \geq 5) = P(X=5)+P(X=6)=0.033+0.00352=0.0365$

Part 3

Let X the random variable of interest, on this case we now that:

$X \sim Binom(n=6, p=0.34)$

The probability mass function for the Binomial distribution is given as:

$P(X)=(nCx)(p)^x (1-p)^{n-x}$

Part 4

Let X the random variable of interest, on this case we now that:

$X \sim Binom(n=4, p=0.69)$

The probability mass function for the Binomial distribution is given as:

$P(X)=(nCx)(p)^x (1-p)^{n-x}$

The expected value is given by:

$E(X)=np=4*0.69=2.76$

The variance $\sigma^2 = np(1-p) = 4*0.69*(1-0.69) =0.8556$

$\sigma=\sqrt{np(1-p)}=\sqrt{4*0.69(1-0.69)}=0.925$

Unusual outcomes would be considered values above or below 2 deviations from the mean for example 2.76-(2*0.925) =0.91 or 2.76+2(0.925)=4.61[/tex]. X=0 and X=4 would be considered as unusual values.

6 0

4 years ago

Divide 1/2÷1/8 and express the answer in simplest terms. If necessary, use / for the fraction bar.​

Divide 1/2÷1/8 and express the answer in simplest terms. If necessary, use / for the fraction bar.