Answer:
500
Step-by-step explanation:
I pressed this by an accident
a = 4, b = 0
Also, a = 0 and b = 0 :)
f(x) = 3x(x-1)(x-3)
f(x) = 3x³-12x²+9x = 3x(x²-4x+3) =
= 3x(x²-x-3x+3) = 3x[x(x-1)-3(x-1)] =
= 3x[(x-1)(x-3)] = 3x(x-1)(x-3)