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3 years ago

Pls help its timed no fake answers i cant afford to fail

Mathematics

1 answer:

SOVA2 [1]2 years ago

8 0

Answer:

It's B, I tried using mathaway and that's the closest to the answer I got. Try it. I always use mathaway for any math problems, use that for now on if you're stuck

Step-by-step explanation:

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Halley has 40 blocks. Daniel has 50 blocks. Molly has 2 groups of 10 blocks.

erik [133]

Answer:

What do you need to answer, you never said

Step-by-step explanation:

6 0

3 years ago

If y varies jointly with x and z and y=90 when x=2 and z=9, find x when y=105 and z=3

Inessa05 [86]

Answer:

Step-by-step explanation:

y & xz

y = kxz

k = y/xz

When y = 90, x = 2 and z = 9

k = 90/(2×9) = 10/2

k = 5

y = 5xz

When y = 105 and z = 3

105 = 5×3x

105 = 15x

x = 105/15

x = 7

3 0

3 years ago

What are the factors of 4x2 + 23x − 6?

katen-ka-za [31]

4 $x^{2}$ +23x-6
(4 $x^{2}$ -x)+(24x-6)
x(4x-1)+6(4x-1)
(4x-1)(x+6)

4 0

3 years ago

Read 2 more answers

HELP!!!!!!!!!

wel

Answer:

$y=-\frac{2}{3} x+4$

Step-by-step explanation:

move the variable to the right(-2x) and change the sign(2x now) -3y=-12+2x then change the signs (-3y is 3y , -12 is 12 and then 2x becomes -2x again) then divide both sides of the equation by 3 so 12÷3=4 and -2x÷3= $-\frac{2}{3} x$ then you're going to use the commutative property to reorder the terms . so your answer is $y=-\frac{2}{3} x+4$

3 0

2 years ago

The probability that a college student uses Twitter for social networking is 0.92 if 9 students are chosen at random use the bin

KonstantinChe [14]

Answer:

0.8417

Step-by-step explanation:

The probability that a college student uses Twitter for social networking is $p=0.92,$ then the probability that a college student does not use Twitter for social networking is $q=1-p=1-0.92=0.08.$

9 students are chosen at random.

Use the binomial probability formula to find the probability that 8 use Twitter:

$C^9_8p^8q^{9-8}=9\cdot (0.92)^8\cdot (0.08)^1\approx 0.3695$

Use the binomial probability formula to find the probability that 9 use Twitter:

$C^9_9p^9q^{9-9}=1\cdot (0.92)^9\cdot (0.08)^0\approx 0.4722$

The probability that more than 7 students use Twitter is

$0.3695+0.4722=0.8417$

6 0

3 years ago