Step-by-step explanation:
You need to use trigonometric stuff here. Since you're given the hypotenuse and an angle you can plug that right into an equation.
Recall that sin is opposite over hypotenuse and cos is adjacent over hypotenuse.

Now that you know the opposite side (DC) you can use tan, too, but I'm going to use cos.

This is the adjacent side (BC). I put it in its exact value, but in decimal form it's ≈12.124.
Now you can do the perimeter:

Your answer is the 38.2
Answer:
(-5, 2)
Step-by-step explanation:
The answer is where the two lines intersect
Answer: Secant of angle A = √2
Step-by-step explanation:
From the given right angle triangle,
AB represents the hypotenuse of the right angle triangle.
With m∠B as the reference angle,
AC represents the adjacent side of the right angle triangle.
BC represents the opposite side of the right angle triangle.
To determine Cosine of m∠A, we would apply
the cosine trigonometric ratio.
Cos θ = adjacent side/hypotenuse. Therefore,
Cos A = √5/√10
Secant = 1/Cosine
Therefore,
Secant of angle A = √10/√5 = √2
Answer:
-12.5x <u><</u> -25
hope this helps :) plz brainliest
Step-by-step explanation:
Answer:
Step-by-step explanation:
1. x -> opposite side of 48°
o → hypotenuse
b → adjacent side of 48°

o = 20.27

b = 0.67*20.27
b = 13.58
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
2) i → opposite side of 25°
n → adjacent side of 25°

i = 12.6

n = 27.3
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
3) a → opposite side of 70°
e → adjacent side of 70°

a = 23.5

e = 8.5
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
4)

x = 59.25

z = 46.5