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Airida [17]
3 years ago
10

N+ 7 = 21 What step is needed to solve the equation and what is the solution to the equation ?

Mathematics
2 answers:
kozerog [31]3 years ago
8 0
Subtraction is needed n = 14
Nimfa-mama [501]3 years ago
4 0

Answer:

n+7=21 -7

n=14

Step-by-step explanation:

prove me wrong

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What is the solution to the linear equation?
antoniya [11.8K]

Answer:

\large\boxed{p=1}

Step-by-step explanation:

\dfrac{2}{5}+p=\dfrac{4}{5}+\dfrac{3}{5}p\qquad\text{multiply both sides by 5}\\\\5\!\!\!\!\diagup^1\cdot\dfrac{2}{5\!\!\!\!\diagup_1}+5p=5\!\!\!\!\diagup^1\cdot\dfrac{4}{5\!\!\!\!\diagup_1}+5\!\!\!\!\diagup^1\cdot\dfrac{3}{5\!\!\!\!\diagup_1}p\\\\2+5p=4+3p\qquad\text{subtract 2 from both sides}\\\\5p=2+3p\qquad\text{subtract 3p from both sides}\\\\2p=2\qquad\text{divide both sides by 2}\\\\p=1

4 0
3 years ago
Read 2 more answers
ABCD and EFGH are squares. If JH= 4cm and JC=9cm, then what is the area of the shaded region?
romanna [79]
The squares are shown in the attached picture.

As you can see, JC is half the diagonal of ABCD and JH is half the diagonal of EFGH.

In order to find the area of the shaded figure, we need to subtract the area of the white square (EFGH) from the area of the big square (ABCD).

The area of a square know the diagonal is given by the formula:
A = d² ÷ 2

A(ABCD) = (2×JC)² ÷ 2
                = (2×9)² ÷ 2
                = 162 cm²

A(EFGH) = (2×JH)² ÷ 2
               = (2×4)² ÷ 2
               = 32 cm²

Therefore:
A = A(ABCD) - <span>A(EFGH)
   = 162 - 32
   = 130 cm</span>²

The area of the shaded region is 130 cm².

3 0
3 years ago
Evaluate each expression for the given value of the variable <br> x-3/10 for x=1/2
faltersainse [42]

x-3/10 for x=1/2

1/2-3/10

=2/10

=1/5

3 0
4 years ago
Can I get help someone​
motikmotik

Answer:

m ≤ 4250

Step-by-step explanation:

What we know:

Mr. Loureiro has to pay $25 plus 10 cents every mile.

The equation becomes 25 + 0.1x = 450

25 + 0.1x = 450

0.1x = 450 - 25

0.1x = 425

x = 4250

So, Mr. Loureiro can travel no more than 4250 mi. (m ≤ 4250)

4 0
3 years ago
The outside diameter (od) of a pipe is 4 9/32 inches. The walls are 7/32 inches thick. find the inside diameter.
sergij07 [2.7K]

The inside diameter would be the outside diameter minus 2 of the wall thicknesses.

4 9/32 - (2 x 7/32)

Simplify:

4 9/32 - 14/32

Because 14/32 is larger than 9/32 change one of the hole numbers to a fraction: 1 = 32/32

rewrite 4 9/32 as 3 41/32

Now subtract:

3 41/32 - 14/32 = 3 27/32 inside diameter.

4 0
3 years ago
Read 2 more answers
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