Answer:

Step-by-step explanation:

The squares are shown in the attached picture.
As you can see, JC is half the diagonal of ABCD and JH is half the diagonal of EFGH.
In order to find the area of the shaded figure, we need to subtract the area of the white square (EFGH) from the area of the big square (ABCD).
The area of a square know the diagonal is given by the formula:
A = d² ÷ 2
A(ABCD) = (2×JC)² ÷ 2
= (2×9)² ÷ 2
= 162 cm²
A(EFGH) = (2×JH)² ÷ 2
= (2×4)² ÷ 2
= 32 cm²
Therefore:
A = A(ABCD) - <span>A(EFGH)
= 162 - 32
= 130 cm</span>²
The area of the shaded region is
130 cm².
Answer:
m ≤ 4250
Step-by-step explanation:
What we know:
Mr. Loureiro has to pay $25 plus 10 cents every mile.
The equation becomes 25 + 0.1x = 450
25 + 0.1x = 450
0.1x = 450 - 25
0.1x = 425
x = 4250
So, Mr. Loureiro can travel no more than 4250 mi. (m ≤ 4250)
The inside diameter would be the outside diameter minus 2 of the wall thicknesses.
4 9/32 - (2 x 7/32)
Simplify:
4 9/32 - 14/32
Because 14/32 is larger than 9/32 change one of the hole numbers to a fraction: 1 = 32/32
rewrite 4 9/32 as 3 41/32
Now subtract:
3 41/32 - 14/32 = 3 27/32 inside diameter.