Find the volume of a cylinder with a radius of 5 cm and a height of 7 cm.
2 answers:
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Step-by-step explanation:
Let a be the price of 1 adult ticket.
Let c be the price of 1 child ticket.
given,
as equation 1,
and
as equation 2.
Now we will solve for a and c using elimination method of simultaneous equations.
Now we multiply equation 2 by 2 to eliminate a and solve for c.
This new equation will be equation 3.
Now we will use equation 1 - equation 3 to eliminate a and solve for c.
Now substitute c into equation 2.
Therefore one adult ticket will cost $17.50 and one child ticket will cost $9.50.
a. Find the graph of their common region in the attachment
b. The area of the common region of the graphs is 8 units²
<h3>a. How to sketch the region common to the graphs?</h3>Since we have x ≥ 2, y ≥ 0, and x + y ≤ 6, we plot each graph separately and find their region of intersection.
- The graph of x ≥ 2 is the region right of the line x = 2.
- The graph of y ≥ 0 is the region above the line y = 0 or x-axis.
- To plot the graph of x + y ≤ 6, we first plot the graph of x + y = 6 ⇒ y = -x + 6. Then the graph of x + y ≤ 6 is the graph of y ≤ - x + 6.
So, the graph of x + y ≤ 6 is the region below the line y = - x + 6
From the graph, the regions intersect at (2, 0), (2, 4) and (6, 0)
Find the graph of their common region in the attachment
<h3>b. The area of the common region</h3>From the graph, we see that the common region is a right angled triangle with
- height = 4 units and
- base = 4 units
So, its area = 1/2 × height × base
= 1/2 × 4 units × 4 units
= 1/2 × 16 units²
= 8 units²
So, the area of the common region of the graphs is 8 units²
Learn more about region common to graphs here:
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The figure is not attached. So, I have attached it from the link- brainly.com/question/4198293
Answer:
Step-by-step explanation:
Label the triangle ABC as shown below.
Given:
AB = 8, BC = 15, AC = 17, m∠ABC = 90°, m∠ACB = 28°, m∠BAC = 62°
The tangent of a given angle is given as the ratio of the opposite side and the adjacent side. The opposite side is the side opposite to the angle. The adjacent side is the other leg of the right angled triangle.
Here, the opposite side to angle A is BC and adjacent side is AB.
Therefore, the tan ratio of angle A is given as:
Hence, tan 62 = 1.875.
