All categories

3 years ago

Please help meee

Mathematics

1 answer:

coldgirl [10]3 years ago

3 0

Answer:

its congruent because of the lines

You might be interested in

What is solution set for the quadratic equation ×^2 + 10×+25=0

Roman55 [17]

Answer:

x=-5

Step-by-step explanation:

x squared+10x+25 factors into (x+5)(x+5). Set x equal to 0 and you get x=-5. To check, plug in negative 5 and you get 25+ -50 + 25=0 which is true.

7 0

3 years ago

2√48 - 3√12 + 3√27 mmm

algol13

Answer:

Step-by-step explanation:

4 0

3 years ago

Lucy's final exam has true/false questions, worth 2 points each, and multiple choice questions, worth 3 points each. Let x be th

Bad White [126]

True/False questions = 2 points each(x).
Multiple choice questions = 3 points each(y).
She needs more than (>) 90 points.

2x + 3y > 90

4 0

3 years ago

Read 2 more answers

Factor the trinomial: <br>x^2-8x-33<br><br>please help I'm stumped

Anon25 [30]

-33=-11*3
-8=-11+3
so
(x-11)(x+3)

8 0

3 years ago

Read 2 more answers

Write an equation of the perpendicular bisector of the segment with the endpoints (8,10) and ( -4,2).

ale4655 [162]

Answer:

The required equation is:

$y = -\frac{3}{2}x+9$

Step-by-step explanation:

To find the equation of a line, the slope and y-intercept is required.

The slope can be found by finding the slope of given line segment. A the perpendicular bisector of a line is perpendicular to the given line, the product of their slopes will be -1 and it will pass through the mid-point of given line segment.

Given points are:

$(x_1,y_1) = (8,10)\\(x_2,y_2) = (-4,2)$

We will find the slope of given line segment first

$m = \frac{y_2-y_1}{x_2-x_1}\\= \frac{2-10}{-4-8}\\=\frac{-8}{-12}\\=\frac{2}{3}$

Let m_1 be the slope of perpendicular bisector then,

$m.m_1 = -1\\\frac{2}{3}.m_1 = -1\\m_1 = \frac{-3}{2}$

Now the mid-point

$(x,y) = (\frac{x_1+x_2}{2} , \frac{y_1+y_2}{2})\\= (\frac{8-4}{2} , \frac{10+2}{2})\\=(\frac{4}{2}, \frac{12}{2})\\=(2,6)$

We have to find equation of a line with slope -3/2 passing through (2,6)

The equation of line in slope-intercept form is given by:

$y = m_1x+b$

Putting the value of slope

$y= -\frac{3}{2}x+b$

Putting the point (2,6) to find the y-intercept

$6 = -\frac{3}{2}(2)+b\\6 = -3+b\\b = 6+3 =9$

The equation is:

$y = -\frac{3}{2}x+9$

7 0

3 years ago