Let (a) be the first cat
let (b) be the second cat
a +b=11kg-----(1)
a=b+1500g⇒(1.5 kg)-------(2)
so now u have a system of two unknowns
a=11-b
substitute a in (2)
11-b=b+1.5
11-1.5=2b
2b=9.5
b=9.5/2=4.75
subs. b in (1)
a+b=11
a+4.75=11
a=11-4.75=6.25
so cat (a) is 6.25 kg
and (b) is 4.75 kg
hope I helped
---------------------------------------------------------------------
Calculate the spray interval to spray 5 times a day
----------------------------------------------------------------------
one day = 24 hour
24 ÷ 5 = 4.8 hours
----------------------------------------------------------------------
Find the interval in minutes
----------------------------------------------------------------------
4.8 hours = 4h 48 mins
4.8 hours = (4 x 60) + 48
4.8 hours =288 mins
----------------------------------------------------------------------
Answer: 288 mins
----------------------------------------------------------------------
Put T in the interior of <OPQ. P is the vertex of the angle. Join PT
Answer:
1/2x or x/2
Step-by-step explanation:
You're taking the number you started with and either multiplying it by 1/2 half or dividing it by 2.
