Answer: O a layer of grass clippings, a layer of fruit scraps, some soil, and some water
Explanation:
The compost pile is made up of decomposing organic materials that are obtained from dead and decaying vegetable or plant matter, animal materials like dung, dead skins and others. The decomposition is done by the soil microbes that recycle the matter into nutrients that are absorbed by the plants. All the components of the compost pile are degradable and completely converted into organic matter. The grass clipping and fruit scraps mixed with soil and water can be easily decomposed by the soil microbes easily.
For this problem, we use the Faradays law to relate the mass electroplated and the current passed through. We do as follows:
60.1 g (1 mol / 196.67 g) (1 mol e- / 1 mol Au) ( 96500 C / 1 mol e- ) = 29486.25 C
Q = It
29486.25 = 5t
t = 5897.85 s = 98.30 min
Hope this answers the question.
Answer:
The density of gold is 19. 38 ![\frac{g}{mL}](https://tex.z-dn.net/?f=%5Cfrac%7Bg%7D%7BmL%7D)
Explanation:
Density is defined as the property that matter, whether solid, liquid or gas, has to compress in a given space. In other words, density is a quantity that allows you to measure the amount of mass in a given volume of a substance. So, the expression for the calculation of the density is the quotient between the mass of a body and the volume it occupies:
![density=\frac{mass}{volume}](https://tex.z-dn.net/?f=density%3D%5Cfrac%7Bmass%7D%7Bvolume%7D)
Density, according to the International System of Units, is usually expressed in kilogram per cubic meter (kg/m³) or gram per cubic centimeter (g/cm³). Although it can also be expressed in any other unit of mass by volume.
In this case:
- mass= 96.9 grams
- volume= 5 mL
Replacing:
![density=\frac{96.9 g}{5 mL}](https://tex.z-dn.net/?f=density%3D%5Cfrac%7B96.9%20g%7D%7B5%20mL%7D)
density=19. 38 ![\frac{g}{mL}](https://tex.z-dn.net/?f=%5Cfrac%7Bg%7D%7BmL%7D)
The density of gold is 19. 38
, that you could approximate the option 19. 32 ![\frac{g}{mL}](https://tex.z-dn.net/?f=%5Cfrac%7Bg%7D%7BmL%7D)