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3 years ago

In which substance does phosphorus have a +3 oxidation state

1 answer:

4 0

Options are as follow,

A. P₄O₁₀
B. PCl₅
C. Ca₃(PO₄)₂
<span>D. KH</span>₂PO₃

Answer;
The correct option is Option-D (KH₂PO₃).

Explanation:
Oxidation number of Phosphorous is calculated as,

As the normal oxidation number of K is +1, H is +1 and O is -2 so,

KH₂PO₃ = 0

0 shows that the molecule is neutral. Now puttion values of all elemnts except P,

(+1) + (+1)₂ + P + (-2)₃ = 0

+1 + 2 + P - 6 = 0

+3 + P - 6 = 0

+3 + P = +6

P = +6 - 3

P = +3

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Which of these is the smallest volume 500mL, 2,500 cm3, 5.5•10-1, 25 m3

mezya [45]

25m³.
500mL = 500cm³
25m³ = 2,500cm³
5.5x9 = 49.5(cm³)
25m³ is the smallest among the others.

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3 years ago

A sample of an unknown substance has a mass of 0.158 kg. If 2,510.0 J of heat is required to heat the substance from 32.0°C to 6

Alexxandr [17]

Specific heat capacity is the required amount of heat per unit of mass in order to raise teh temperature by one degree Celsius. It can be calculated from this equation: H = mCΔT where the H is heat required, m is mass of the substance, ΔT is the change in temperature, and C is the specific heat capacity.

H = m<span>CΔT
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3 years ago

When a substance is entering a phase change, the gain or loss of heat is a result of:______.

nydimaria [60]

When a substance is entering a phase change, the gain or loss of heat is a result of energy gained or lost in forming or breaking intermolecular interaction.

The constant temperatures occur when a substance is undergoing a phase transition. If heat is removed from a substance , such as in freezing and condensation , then the process is exothermic . In this instance , heat is decreasing the speed of the molecules causing then move slower.

Example : liquid to solid and gas to liquid .

These changes release heat to the surrounding.

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2 years ago

A chemist dissolves 699. mg of pure hydrobromic acid in enough water to make up 180. mL of solution. Calculate the pH of the sol

Sedaia [141]

Answer: 1.32

Explanation:

First, we must obtain the molar mass of HBr. After that, we try to obtain the concentration of the hydrobromic acid from the formula n=CV since the volume of solution and mass of acid was provided. Recall that n=m/M. If the concentration of acid is thus obtained, we make use of the fact that the concentration of H+ in the acid is equal to the molar concentration of HBr to obtain the pH. The pH is the negative logarithm of the concentration we obtained in the initial step.

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3 years ago

Balance this equation and pick the answer with the coefficients that belong there.

geniusboy [140]

Answer:

2,3,6,1

Explanation:

The unbalanced reaction expression is given as:

AlBr₃ + K₂SO₄ → KBr + Al₂(SO₄)₃

We need to balanced this reaction equation. Our approach is a mathematical method where we assign variable a,b,c and d as the coefficients.

aAlBr₃ + bK₂SO₄ → cKBr + dAl₂(SO₄)₃

Conserving Al; a = 2d

Br: 3a = c

K: 2b = c

S: b = 3d

O: 4b = 12d

Let a = 1, c = 3, d = $\frac{1}{2}$ b = $\frac{3}{2}$

Multiply through by 2 to give;

a = 2, b = 3, c = 6 and d = 1

2AlBr₃ + 3K₂SO₄ → 6KBr + Al₂(SO₄)₃

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2 years ago