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2 years ago

What is the equation of the line x–3y=18in slope-intercept form?

Mathematics

1 answer:

Alekssandra [29.7K]2 years ago

5 0

Answer:

$y=\frac{1}{3} x-6$

Step-by-step explanation:

Write down the slope-intercept form:

$y=mx+b$

Where m is the slope and b is the y-intercept.

To turn the equation into slope-intercept form, isolate y on the left-hand side:

$x-3y=18\\-3y=18-x\\y=-6+\frac{x}{3} \\$

Rearrange the equation a bit:

$y=\frac{1}{3} x-6$

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If m=2,n=5 and y =3, evaluate

svlad2 [7]

Answer:

here you go :)

Step-by-step explanation:

Replace the variables with their corresponding values:

$\frac{2(5+3)}{2*5}$

Cancel out 2 in both numerator and denominator.

$\frac{3+5}{5}$

Add 3 and 5 to get 8.

$\frac{8}{5}$

Finally, divide 8 by 5 to get your answer:

$\frac{8}{5} = 1.6$

Your answer is (a) 1.6

<h2>Hope this helps! :)</h2>

3 0

2 years ago

A man ears $15.50 per hour with time and a half for overtime and he worked 46 hours during a recent week. Find his gross pay for

irina [24]

Answer:

525267262525226

Step-by-step explanation:

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6 0

2 years ago

the vertex of this parabola is at (3,5). When the y-value is 6, the x-value is -1. What is the coefficient of the squared term i

otez555 [7]

Now, assuming is a vertical parabola, so the squared variable is the "x", let's do some checking.

$\bf \qquad \textit{parabola vertex form}\\\\
\begin{array}{llll}
\boxed{y=a(x-{{ h}})^2+{{ k}}}\\\\
x=a(y-{{ k}})^2+{{ h}}
\end{array} \qquad\qquad vertex\ ({{ h}},{{ k}})\\\\
-------------------------------\\\\
vertex
\begin{cases}
h=3\\
k=5
\end{cases}\implies y=a(x-3)^2+5
\\\\\\
\textit{we also know that }
\begin{cases}
y=6\\
x=-1
\end{cases}\implies 6=a(-1-3)^2+5
\\\\\\
1=a(-4)^2\implies 1=16a\implies \cfrac{1}{16}=a$

6 0

3 years ago

Solve pls brainliest

kipiarov [429]

The answer should be 4.3 (the line is ontop of the 3)

The line is on the 3

6 0

2 years ago

Find the area, to the nearest hundredth, of the figure

ehidna [41]

Answer:

Step-by-step explanation:

hypotenuse = √(14.4² + 6²) = √243.36 = 15.6 mi

area of triangle = 0.5×6×14.4 = 43.2 mi²

radius of semicircle = 15.6/2 = 7.8

area of semicircle = πr² = 60.84π mi²

total area = 43.2 + 60.84π ≅ 234.33 mi²

5 0

3 years ago