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Lera25 [3.4K]
2 years ago
13

Can someone help please lol

Mathematics
1 answer:
boyakko [2]2 years ago
8 0

Answer:

1. (an closed circle) on the negative 2 mark, then shade everything on the right. (Meaning anything greater than -2, such as -1, 0, 1, 2)

2. (an open circle) on the positive 3 mark, then shade everything right. (Meaning anything greater than 3, such as 4, 5, 6)

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Examine the linear table to find the slope, y-intercept, and write the equation for this linear relationship ​. NEED HELP PLEASE
gizmo_the_mogwai [7]

Answer:

y = \frac{4}{3} x + 17  

Step-by-step explanation:

The table shows a set of x and y values, thus showing a set of points we can use to find the equation.

1) First, find the slope by using two points and substituting their x and y values into the slope formula, \frac{y_2-y_1}{x_2-x_1}. I chose (-3, 13) and (0,17), but any two points from the table will work. Use them for the formula like so:

\frac{(17)-(13)}{(0)-(-3)} \\= \frac{17-13}{0+3} \\= \frac{4}{3}

Thus, the slope is \frac{4}{3}.

2) Next, identify the y-intercept. The y-intercept is where the line hits the y-axis. All points on the y-axis have a x value of 0. Thus, (0,17) must be the y-intercept of the line.

3) Finally, write an equation in slope-intercept form, or y = mx + b format. Substitute the m and b for real values.

The m represents the slope of the equation, so substitute it for \frac{4}{3}. The b represents the y-value of the y-intercept, so substitute it for 17. This will give the following answer and equation:

y = \frac{4}{3} x + 17

7 0
3 years ago
Use the standard norml distribution or the t-distribution to construct a 99% confidence interval for the population mean. Justif
dalvyx [7]

Answer:

E) we will use t- distribution because is un-known,n<30

the confidence interval is (0.0338,0.0392)

Step-by-step explanation:

<u>Step:-1</u>

Given sample size is n = 23<30 mortgage institutions

The mean interest rate 'x' = 0.0365

The standard deviation 'S' = 0.0046

the degree of freedom = n-1 = 23-1=22

99% of confidence intervals t_{0.01} =2.82  (from tabulated value).

The mean value = 0.0365

x±t_{0.01} \frac{S}{\sqrt{n-1} }

0.0365±2.82 \frac{0.0046}{\sqrt{23-1} }

0.0365±2.82 \frac{0.0046}{\sqrt{22} }

0.0365±2.82 \frac{0.0046}{4.690 }

using calculator

0.0365±0.00276

Confidence interval is

(0.0365-0.00276,0.0365+0.00276)

(0.0338,0.0392)

the mean value is lies between in this confidence interval

(0.0338,0.0392).

<u>Answer:-</u>

<u>using t- distribution because is unknown,n<30,and the interest rates are not normally distributed.</u>

4 0
3 years ago
Which weights more 2.48 or 2.5​
Mazyrski [523]
2.5 weighs more. It’s a greater number than 2.48
6 0
2 years ago
2/3 times 3/4 in simplest form
cestrela7 [59]

Answer:

1/2

Step-by-step explanation:

2/3 times 3/4 is 6/12, and 6/12 in simplest form is 1/2.

3 0
3 years ago
7. Which correctly describes the graph shown
KATRIN_1 [288]

Answer:

A) linear; function

Step-by-step explanation:

hope this helps and hope you have a good day and please mark me brainliest

8 0
3 years ago
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