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Vesna [10]
3 years ago
8

Help the blue dot is at what value on the number line

Mathematics
2 answers:
alex41 [277]3 years ago
8 0
Answer: 20
explanation: count by 2’s
Artemon [7]3 years ago
5 0

Answer:

20

Step-by-step explanation:

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In rhombus MOTH, angle HTM=(5x+6) degrees. If angle HMO=(12x-6)degrees, what is angle HMO?
forsale [732]

Answer:

m∠HMO=102°

Step-by-step explanation:

we know that

In a Rhombus the diagonals bisect the angles and opposite angles are equal

In this problem

Angles HMO and HTO are opposite angles

m∠HMO=m∠HTO

m∠HTM=(1/2)m∠HMO ----> because the diagonals bisect the angles and opposite angles are congruent

substitute the values

(5x+6)\°=(1/2)(12x-6)\°

solve for x

10x+12=12x-6\\12x-10x=12+6\\2x=18\\x=9

<em>Find the measure of angle HMO</em>

m∠HMO=(12x-6)°

substitute the value of x

m∠HMO=(12(9)-6)=102°

see the attached figure to better understand the problem

5 0
3 years ago
What is the linear factorization of the function F(x) = 5x^3 + 5x ?
Aliun [14]
5x^3 + 5x = 5x(x^2 + 1)
5 0
4 years ago
Lisa invested $5200 in a savings account with a yearly interest rate of 6% for
andrey2020 [161]

P is the principal amount, $5200.00.

r is the interest rate, 6% per year, or in decimal form, 6/100=0.06.

t is the time involved, 9....year(s) time periods.

So, t is 9....year time periods.

To find the simple interest, we multiply 5200 × 0.06 × 9 to get that: 

The interest is: $2808.00

4 0
3 years ago
Read 2 more answers
What is 1.05 as an improper fraction
lozanna [386]
21/20 ,because 0.5 is 1/20 of the whole number 1,so 20/20 + 1/20=21/20
5 0
3 years ago
For each geometric sequence, write a recusive rule by finding the commom ratio by calculating the ration of consecutive terms. W
Inessa05 [86]

Answer:

a_n=2.(3)^{n-1}

Step-by-step explanation:

Given sequence is:

2,6,18,54,162

So the common ratio can be found by dividing the second term by first term:

r = 6/2 = 3

The standard formula for geometric sequence is:

a_n=a_1r^{n-1}

Putting the value of r

a_n=2.(3)^{n-1}

So,

a_1=2.(3)^{1-1} => 2.3^0 = 2*1 = 2\\a_2=2.(3)^{2-1} => 2.3^1 = 2*3 = 6\\a_3=2.(3)^{3-1} => 2.3^2 = 2*9 = 18\\a_4=2.(3)^{4-1} => 2.3^3 = 2*27 = 54\\a_5=2.(3)^{5-1} => 2.3^4 = 2*81 = 162

3 0
3 years ago
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