Anyone know the answer to this?

Mathematics

1 answer:

Gelneren [198K]2 years ago

3 0

2n^2/6^2+10n-1

Step-by-step explanation:

(6-n)(6+n)-(6+n)(6+n)/(6+n)(6+n)-(1-n)(1+n)

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Help me ASAP I’ll mark you as a BL Question attached below

mojhsa [17]

Answer:

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Step-by-step explanation:

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8 0

3 years ago

Solve quadratic equations by factoring<br> x cubed +3x squared - 4x= 0

Papessa [141]

<span>x cubed +3x squared - 4x= 0
= x^3 + 3x^2 -4x = 0
=x(x^2 +3x -4) = 0
= x (x+4)(x-1) = 0

x = 0
x+ 4 = 0 then x = -4
x - 1 = 0 then x = 1
answer: x = 0, x = -4 and x = 1</span>

8 0

3 years ago

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you draw two marbles without replacement from a bag containing four red marbles, two Yellow Marbles and five blue marbles, find

AleksAgata [21]

A bag contains four red marbles, two Yellow Marbles and five blue marbles.

Two marbles are drawn at random without replacement.

Total number of marbles are,

$4\text{ + 2 + 5 = 11}$

There are 11 ways to select first marble and 10 ways to select second marble.

The total number of possible outcomes are calculated as,

$Total\text{ number of outcomes = 11 }\times\text{ 10 = 110 }$

Thus the total number of possible outcomes are 110.

7 0

1 year ago

Write a definite integral that represents the area of the region. (Do not evaluate the integral.)

joja [24]

Answer:

$\int_{-1}^{1}7(x^{3}-x)\:dx$

Step-by-step explanation:

1) The other curve is $y=0$ then the common points of both curves are x-intercepts, the roots of $y=7(x^{3}-x)$

$y=7(x^{3}-x)\Rightarrow 7(x^3-x)=0 \Rightarrow 7(x^{3}-x)=7x(x-1)(x-1)\Rightarrow \\S=\left ( 0,0 \right ),\left ( -1,0 \right ),\left ( 1,0 \right )$