y=x vertical compression compression by a factor of 1/7 please compress the equation of y=x by a vertical compression of 1/7

Mathematics

1 answer:

damaskus [11]3 years ago

6 0

Answer: y = 1/7(x) or y = x/7

Step-by-step explanation:

Hey there! Thank you for submitting your question to Brainly!

In order to vertically compress the equation y = x by 1/7, we would simply need to multiply x by 1/7. Therefore, this gives us the equation y=1/7(x) or y=x/7.

Hope this helps!! :)

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svet-max [94.6K]

Well can you put a pic

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2 years ago

Show all work and provide necessary descriptions

masya89 [10]

Let

$P=(P_x,P_y),\quad Q=(Q_x,Q_y)$

If M is the midpoint, the x and y coordinates of M are the average of the x and y coordinates of P and Q:

$M=\left(\dfrac{P_x+Q_x}{2},\ \dfrac{P_y+Q_y}{2}\right)$

We can solve this expression for the coordinates of Q:

$M_x = \dfrac{P_x+Q_x}{2} \implies Q_x = 2M_x-P_x$

$M_y = \dfrac{P_y+Q_y}{2} \implies Q_y = 2M_y-P_y$

Plug in the values for the coordinates of M and P to get

$Q_x = 2M_x-P_x = 2\cdot 5-11 = 10-11=-1$

$Q_y = 2M_y-P_y = 2\cdot (-2) - (-10) = -4+10=6$

5 0

3 years ago

Show with work please.

kolbaska11 [484]

Answer:

$\csc \left(\theta-\frac{\pi }{2}\right)=0.73$

Step-by-step explanation:

The identity you will use is:

$\csc \left(x\right)=\frac{1}{\sin \left(x\right)}$

So,

$\csc \left(\theta-\frac{\pi }{2}\right)$

$\csc \left(\theta-\frac{\pi }{2}\right)=\frac{1}{\sin \left(-\frac{\pi }{2}+\theta\right)}$

Now, using the difference of sin

Note: state that $\text{sin}(\alpha\pm \beta)=\text{sin}(\alpha) \text{cos}(\beta) \pm \text{cos}(\alpha) \text{sin}(\beta)$

$\csc \left(\theta-\frac{\pi }{2}\right)=\frac{1}{-\cos \left(\theta\right)\sin \left(\frac{\pi }{2}\right)+\cos \left(\frac{\pi }{2}\right)\sin \left(\theta\right)}$