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3 years ago

Help please... dont answer if u dont know bc this is for a grade

Mathematics

2 answers:

emmasim [6.3K]3 years ago

6 0

The answer is A !!!

salantis [7]3 years ago

3 0

The answer is a !!!!!

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What is the length of the line segment with endpoints (−3,8) and (7, 8) ?

Fudgin [204]

Ur answer would be 10 units

5 0

3 years ago

An unbalanced die is manufactured so that there is a 20% chance of rolling a “six." The die is rolled 6

SIZIF [17.4K]

Answer:

Probability of rolling at least 4 sixes is 0.01696.

Step-by-step explanation:

We are given that an unbalanced die is manufactured so that there is a 20% chance of rolling a “six." The die is rolled 6 times.

The above situation can be represented through binomial distribution;

$P(X = r) = \binom{n}{r} \times p^{r} \times (1-p)^{n-r};x=0,1,2,3,.......$

where, n = number trials (samples) taken = 6 trials

r = number of success = at least 4

p = probability of success which in our question is probability of

rolling a “six", i.e; p = 0.20

Let X = Number of sixes on a die

So, X ~ Binom(n = 6, p = 0.20)

Now, Probability of rolling at least 4 sixes is given by = P(X $\geq$ 4)

P(X $\geq$ 4) = P(X = 4) + P(X = 5) + P(X = 6)

= $\binom{6}{4} \times 0.20^{4} \times (1-0.20)^{6-4}+\binom{6}{5} \times 0.20^{5} \times (1-0.20)^{6-5}+\binom{6}{6} \times 0.20^{6} \times (1-0.20)^{6-6}$

= $15 \times 0.20^{4} \times 0.80^{2}+6 \times 0.20^{5} \times 0.80^{1}+1 \times 0.20^{6} \times 0.80^{0}$

= 0.0154 + 0.00154 + 0.000064

= 0.01696

Therefore, probability of rolling at least 4 sixes is 0.01696.

8 0

3 years ago

Show your work as you go along.

lana66690 [7]

2x+3(2x-4y)+8y-2
2x+6x-12y+8y-2
8x-12y+8y-2
8x-4y-2

8 0

4 years ago

Help ASAP ill give you brainlist. but explain

Lyrx [107]

Answer:

b, 45

Step-by-step explanation:

The spinner shown has eight congruent sections. The spinner is spun 120 times. What is a reasonable prediction for the number of times the spinner will land on an even number?

Before I begin, let's go over probability.

The probability of an event is: (the number of ways something can happen) / (total number of outcomes possible). So, for example, the probability of rolling a one on a die can be found like:

There is 1 way to roll a one, and 6 possible sides, so the probability is 1/6.

And, if we were to roll the die 60 times, we could expect about 1/6 of the times to be a one, so we should expect a one to be rolled 1/6 * 60 = 10 times.

Now, onto the problem.

Each portion is congruent (they all have the same area). Thus, there is a 1/8 chance of landing on 1, a 1/8 chance of landing on 9, etc.

5 sections are odd, while 3 sections are even. So, the chance of landing on an even number is:

(3 ways to land on an even number) / (8 possible outcomes) = 3/8

If there is a 3/8 possibility to land on even, and there are 120 outcomes, we can say that an even number statistically should be rolled 3/8 * 120 times.

3/8 * 120 = 45

Thus, the answer is b, 45 times

Just in case, let's check the answer by finding the number of times we should roll an odd number and adding it to the number of even times and if it adds up to 120, then the answer is correct.

Because there is a 5/8 chance of getting an odd number, there should be about 5/8 * 120 = 75 times that an odd number is spun.

75 + 45 = 120, so the answer is correct.

I hope this helps! Feel free to ask any questions!

4 0

3 years ago

One water molecule has 2 hydrogen atoms to 1 oxygen atom how many hydrogen atoms are in 4 water molecules

lutik1710 [3]

One water molecule ?4 hydrogen atom in

8 0

3 years ago