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alexgriva [62]
3 years ago
7

What is the cube root of 64? Help plz I need this for my math homework

Mathematics
2 answers:
olga55 [171]3 years ago
6 0

Answer:

4

Step-by-step explanation:

4 because 4*4*4 is 64

Nutka1998 [239]3 years ago
5 0

Answer:

4*4*4 is 64

So it is 4

Step-by-step explanation:

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-3 (n + 6) + 10 = -83 I NEED HELP ASAP!!!!!!!
Marina CMI [18]

Answer:

n=25

Step-by-step explanation:

-3n-8=-83

-3n-8+8=-83+8

-3n=-75

n=25

7 0
3 years ago
How much heat is released when 12. 0 grams of helium gas condense at 2. 17 K? The latent heat of vaporization of helium is 21 J/
aleksandr82 [10.1K]

The amount of heat released when 12.0g of helium gas condense at 2.17 K is; -250 J

The latent heat of vapourization of a substance is the amount of heat required to effect a change of state of the substance from liquid to gaseous state.

However, since we are required to determine heat released when the helium gas condenses.

The heat of condensation per gram is; -21 J/g.

Therefore, for 12grams, the heat of condensation released is; 12 × -21 = -252 J.

Approximately, -250J.

Read more on latent heat:

brainly.com/question/19863536

7 0
2 years ago
(3x-40°)=(2x-10°) for x​
PSYCHO15rus [73]
I think the answer is x=30
5 0
3 years ago
Help me complete this
frutty [35]

Answer:

x = 9.9 in.

Step-by-step explanation:

area of triangle = base * height /2

49 = x*x /2

49*2 = x^2

98 = x^2

\sqrt{98} = x

7\sqrt{2} = x

9.9 = x

3 0
3 years ago
Simplify the following: a) [ -6 +22 – 6 + 8 ] ÷ ( -9 ) b) 400 ÷ { 40 – (-2) -3 – ( -1)} c) 40 x -23 + 40 x -17 d) 1673 x 99 – (-
oee [108]

Step-by-step explanation:

<h3> a) [ -6 +22 – 6 + 8 ] ÷ ( -9 )</h3>

[ -6 +22 – 6 + 8 ] = 18

18 ÷ (-9) = -2

<h3> b) 400 ÷ { 40 – (-2) -3 – ( -1)} </h3>

{40 – (-2) -3 – ( -1)} = { 40 + 2 -3 + 1} = 40

400 ÷ 40 = 10

<h3>c) 40 x -23 + 40 x -17 </h3>

(40 x 23) + (40 x -17)

920 + (-680)

= 240

<h3>d) 1673 x 99 – (-1673) </h3>

(1673 x 99) + 1673

1673 x 100

= 167300

<h3>e) 490 x 98 = 48020</h3>

Hope this helps ^-^

7 0
3 years ago
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