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hram777 [196]
3 years ago
7

Find the slope of the line that passes through (0, -5) and (3, -4)

Mathematics
1 answer:
Scorpion4ik [409]3 years ago
4 0

Answer: I believe it is 2

slope=y2-y1/x2-x1

y2-y1= (0,-3)

x2-x1= (4,5)

m=5-(-3)/4-0

m=2

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What is m∠AEB?<br><br><br><br> Enter your answer in the box.
avanturin [10]
Angle AEB and angle CED are vertical angles, this means they equal each other, therefore we set their values as an equation and solve:

5x-10=3x+40
Subtract 3x to both sides
2x-10=40
Add 10 to both sides
2x=50
Divide both sides by 2
x=25

After we have gotten the value of x we can plug it in into the equation of angle AEB:

5x-10
Substitute x by 25
5(25)-10
Distribute
125-10
Substract
115

The measurement of angle AEB is 115

Hope it helped!, have a great day.
7 0
3 years ago
joy makes 2 3/4 pounds of sunflower seeds she wants to make 1/8 pounds bags of the sunflower seeds for snacks how many bags can
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Answer:

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Step-by-step explanation:

8 0
3 years ago
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mafiozo [28]
Answer: top left
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6 0
2 years ago
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Which of the following lines will have a negative slope? Select all that apply
mariarad [96]
I think it is 1, 4, and 5
6 0
2 years ago
Arlo invested $4000 in an account that earns 5.5% interest, compounded annually. The formula for compound interest is A(t)=P(1+i
USPshnik [31]

\bf ~~~~~~ \textit{Compound Interest Earned Amount} \\\\ A=P\left(1+\frac{r}{n}\right)^{nt} \quad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\dotfill &\$4000\\ r=rate\to 5.5\%\to \frac{5.5}{100}\dotfill &0.055\\ n= \begin{array}{llll} \textit{times it compounds per year}\\ \textit{annually, thus once} \end{array}\dotfill &1\\ t=years\dotfill &4 \end{cases} \\\\\\ A=4000\left(1+\frac{0.055}{1}\right)^{1\cdot 4}\implies A=4000(1.055)^4\implies A\approx 4955.2986

4 0
3 years ago
Read 2 more answers
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