Question

What is the solution to the system of equations

Answer 1

Answer:

Step-by-step explanation:

Hello

I believe there is an error in the question

we have two equations and need to find x and y

$(1) \dfrac{1}{4}x+\dfrac{1}{2}y=\dfrac{5}{8}\\(2) \dfrac{3}{4}x-\dfrac{1}{2}y=3\dfrac{3}{8}$

let s multiply by 8 so that we can get rid of the fractions

(1) becomes 2x+4y=5

(2) becomse 6x-4y=9

if we sum it gives

2x+4y+6x-4y=9+5

8x=14

x = 14/8 = 7/4

and then from the first equation

4y = 5 - 7/4

<=> 16y = 20-7 = 13

y = 13/16

the solutions is (7/4,13/16)