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Which statement describes if there is an extraneous solution to the equation √x-3 = x-5? A. there are no solutions to the equati

Brrunno [24]

Remember that an extraneous solution of an equation, is the solution that emerges from solving the equation but is not a valid solution.

Lets solve our equation to find out what is the extraneous solution:
 $\sqrt{x-3} =x-5$
$(\sqrt{x-3})^2 =(x-5)^2$
$x-3=x^2-10x+25$
$x^2-11x+28=0$
$(x-4)(x-7)=0$
$x-4=0$ and $x-7=0$
$x=4$ and $x=7$

So, the solutions of our equation are $x=4$ and $x=7$ . Lets replace each solution in our original equation to check if they are valid solutions:
- For $x=7$
$\sqrt{x-3} =x-5$
$\sqrt{7-3} =7-5$
$\sqrt{4} =2$
$2=2$
We can conclude that 7 is a valid solution of the equation.

- For $x=4$
$\sqrt{x-3} =x-5$
$\sqrt{4-3} =4-5$
$\sqrt{1} =1$
$1 \neq 1$
We can conclude that 4 is not a valid solution of the equation; therefore, 4 is a extraneous solution.

We can conclude that the correct answer is: D. the extraneous solution is x = 4

7 0

3 years ago

You survey your class and record each students first name, last name, and age. You then make ordered pairs of (first name, age).

ExtremeBDS [4]

Answer: Yes

Step-by-step explanation:

It is a relation because each person will most likely have a different name and you can have plenty of the same outputs just as long as the input doesn't repeat at all.

5 0

3 years ago

Pls help me on this question. Do NOT answer 13 and 15. Only answer 14.

Ilia_Sergeevich [38]

1,700 good luck hope it helps you 100*17=1,700

4 0

3 years ago

Read 2 more answers

An experiment was conducted to investigate whether there is a difference in mean bag strengths for two different brands of paper

Elanso [62]

Answer:

A two-sample t-test for a difference between sample means