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3 years ago

Problem #2 - 8.2B

Mathematics

1 answer:

Bond [772]3 years ago

5 0

Answer J

if you simplify 98 it’ll give you 9.89...

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An automobile went 84 miles on 6.5 gallons of gasoline. At this rate, how many gallons would be needed to travel 126 miles

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Answer:

10 gallons

Step-by-step explanation:

84 ÷ 6.5 =12.9(The unit rate.)

Seeing as one gallon can get you 12.9 miles;

126÷12.9=9.7

So the answers 9.7 gallons, but if you need to round, then 10 to get a whole number.

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Slope-intercept form follows the formula: y=mx+ b

To find the slope intercept form of those, you need to isolate y
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- Steve gathered some data and Steve gathered data and found that the z-score for his salary as compared to other managers with

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( A) is the answer or maybe b)

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Determine the amount you need to invest to have $22,000 dollars in 4 years if you invest at 5% annual interest, compounded quart

zvonat [6]

Answer:

Step-by-step explanation:

Метод

сложных процентов:

S = 100 (1+

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4 years ago

Evaluate the six trigonometric functions of the angle 0.

Arturiano [62]

Given:

Right triangle

To find:

The six trigonometric functions of θ

Solution:

Hypotenuse = 18

Adjacent side to θ = 10

Opposite side to θ = ?

Using Pythagoras theorem:

$\text {Hypotenuse}^2 = \text{adjacent}^2+\text{opposite}^2$

$18^2 =10^2+\text{opposite}^2$

$324=100+\text{opposite}^2$

Subtract 100 from both sides.

$224=\text{opposite}^2$

Taking square root on both sides.

$4\sqrt{14}=\text{opposite}$

Using trigonometric ratio formula:

$$\sin\theta =\frac{\text{opposite }}{\text{hypotenuse}}$

$$\sin\theta =\frac{4\sqrt{14} }{18}$

$$\csc\theta =\frac{\text{hypotenuse}}{\text{opposite }}$

$$\csc\theta =\frac{18}{4\sqrt{14} }$

$$\cos \theta=\frac{\text { adjacent side }}{\text { hypotenuse }}$

$$\cos \theta=\frac{10}{18}$

$$\sec \theta=\frac{\text { hypotenuse }}{\text { adjacent side }}$

$$\sec \theta=\frac{18 }{10}$

$$\tan \theta=\frac{\text { opposite side }}{\text { adjacent side }}$

$$\tan \theta=\frac{4\sqrt{14} }{10}$

$$\cot \theta=\frac{\text { adjacent side }}{\text { opposite side }}$

$$\cot \theta=\frac{10}{4\sqrt{14} }$

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3 years ago